Scala Programming: Find smallest and second smallest elements of a given array

Scala Programming Array Exercise-27 with Solution

Write a Scala program to find smallest and second smallest elements of a given array.

Sample Solution:

Scala Code:

object Scala_Array {

  def main(args: Array[String]): Unit = {
    val arr = Array(5, 6, -9, 6, 15, 4);
    println("Original array:")
    for (x <- arr) {
      print(s"${x}, ")
    }
    var first_element, second_element, arr_size = arr.length;
    /* Return if the array size less than two */
    if (arr_size < 2) {
      println("\nArray size less than two.");
    } else {
      first_element = Int.MaxValue
      second_element = Int.MaxValue

      for (i <- 0 to arr_size - 1) {
        /* Update both first and second if current element is smaller than first. */
        if (arr(i) < first_element) {
          second_element = first_element;
          first_element = arr(i);
        }

        /* Update second if arr[i] is between first and second
               elements.*/
        else if (arr(i) < second_element && arr(i) != first_element)
          second_element = arr(i);
      }
      if (second_element == Integer.MAX_VALUE)
        println("\nNo second smallest element.");
      else
        println(
          s"\nThe smallest element is ${first_element} and second Smallest  element is ${second_element}."
        );
    }
  }
}

Sample Output:

Original array:
5, 6, -9, 6, 15, 4, 
The smallest element is -9 and second Smallest  element is 4.

Scala Code Editor :

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