Scala Programming: Rearrange a given array of unique elements such that every second element of the array is greater than its left and right elements

Scala Programming Array Exercise-37 with Solution

Write a Scala program to rearrange a given array of unique elements such that every second element of the array is greater than its left and right elements.

Example:
Input:
nums= { 1, 2, 4, 9, 5, 3, 8, 7, 10, 12, 14 }
Output:
Array with every second element is greater than its left and right elements:
[1, 4, 2, 9, 3, 8, 5, 10, 7, 14, 12]

Sample Solution:

Scala Code:

object Scala_Array {

  def rearrange_Array_nums(nums: Array[Int]): Array[Int] = {
    var t_nums = 0;
    for (i <- 1 to nums.length - 1 by 2) {
      if (nums(i - 1) > nums(i)) {
        t_nums = nums(i - 1);
        nums(i - 1) = nums(i);
        nums(i) = t_nums;
      }

      if (i + 1 < nums.length && nums(i + 1) > nums(i)) {
        t_nums = nums(i + 1);
        nums(i + 1) = nums(i);
        nums(i) = t_nums;
      }
    }
    nums;
  }

  def main(args: Array[String]): Unit = {
    val nums = Array(1, 2, 4, 9, 5, 3, 8, 7, 10, 12, 14);
    println("Original array:")
    for (x <- nums) {
      print(s"${x}, ")
    }
    val result = rearrange_Array_nums(nums)
    println(
      "\nArray with every second element is greater than its left and right elements:"
    )
    for (x <- result) {
      print(s"${x}, ")
    }
  }
}

Sample Output:

Original array:
1, 2, 4, 9, 5, 3, 8, 7, 10, 12, 14, 
Array with every second element is greater than its left and right elements:
1, 4, 2, 9, 3, 8, 5, 10, 7, 14, 12,

Scala Code Editor :

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