AdventureWorks Database: Find different sales quotas for a employee over next years
SQL Query - AdventureWorks: Exercise-109 with Solution
109. From the following table write a query in SQL to return the difference in sales quotas for a specific employee over subsequent years. Return BusinessEntityID, year, SalesQuota, and the salesquota coming in next row.
Sample table: Sales.SalesPersonQuotaHistory
Sample Solution:
SELECT BusinessEntityID, date_part('year',QuotaDate) AS SalesYear, SalesQuota AS CurrentQuota,
LEAD(SalesQuota, 1,0) OVER (ORDER BY date_part('year',QuotaDate)) AS NextQuota
FROM Sales.SalesPersonQuotaHistory
WHERE BusinessEntityID = 277 AND date_part('year',QuotaDate) IN ('2011','2012');
Sample Output:
businessentityid|salesyear|currentquota|nextquota| ----------------+---------+------------+---------+ 277| 2011.0| 565000| 872000| 277| 2011.0| 872000| 846000| 277| 2011.0| 846000| 952000| 277| 2012.0| 952000| 1600000| 277| 2012.0| 1600000| 1352000| 277| 2012.0| 1352000| 839000| 277| 2012.0| 839000| 0|
SQL AdventureWorks Editor:
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Previous: Find the statistical variance of the sales quota for each quarter.
Next: Compare year-to-date sales between employees for specific terrotery
.
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SQL: Tips of the Day
Concatenate strings of a string field in a PostgreSQL 'group by' query:
Input:
ID COMPANY_ID EMPLOYEE 1 1 Anna 2 1 Bill 3 2 Carol 4 2 Dave
SELECT company_id, string_agg(employee, ', ') FROM mytable GROUP BY company_id;
Output:
COMPANY_ID EMPLOYEE 1 Anna, Bill 2 Carol, Dave
Database: PostgreSQL
Ref: https://bit.ly/2XTiRjq
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