AdventureWorks Database: Return the highest hourly wage for each job title
SQL Query - AdventureWorks: Exercise-125 with Solution
125. From the following tables write a query in SQL to return the highest hourly wage for each job title. Restricts the titles to those that are held by men with a maximum pay rate greater than 40 dollars or women with a maximum pay rate greater than 42 dollars.
Sample table: HumanResources.Employee
Sample table: HumanResources.EmployeePayHistory
Sample Solution:
SELECT JobTitle, MAX(ph1.Rate)AS MaximumRate
FROM HumanResources.Employee AS e
JOIN HumanResources.EmployeePayHistory AS ph1 ON e.BusinessEntityID = ph1.BusinessEntityID
GROUP BY JobTitle
HAVING (MAX(CASE WHEN Gender = 'M'
THEN ph1.Rate
ELSE NULL END) > 40.00
OR MAX(CASE WHEN Gender = 'F'
THEN ph1.Rate
ELSE NULL END) > 42.00)
ORDER BY MaximumRate DESC;
Sample Output:
jobtitle |maximumrate| --------------------------------+-----------+ Chief Executive Officer | 125.5| Vice President of Production | 84.1346| Vice President of Sales | 72.1154| Vice President of Engineering | 63.4615| Chief Financial Officer | 60.0962| Research and Development Manager| 50.4808| Information Services Manager | 50.4808| North American Sales Manager | 48.101| Pacific Sales Manager | 48.101| European Sales Manager | 48.101| Engineering Manager | 43.2692| Finance Manager | 43.2692|
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SQL: Tips of the Day
Difference between natural join and inner join
One significant difference between INNER JOIN and NATURAL JOIN is the number of columns returned-
Consider:
TableA TableB +------------+----------+ +--------------------+ |Column1 | Column2 | |Column1 | Column3 | +-----------------------+ +--------------------+ | 1 | 2 | | 1 | 3 | +------------+----------+ +---------+----------+
The INNER JOIN of TableA and TableB on Column1 will return
SELECT * FROM TableA AS a INNER JOIN TableB AS b USING (Column1); SELECT * FROM TableA AS a INNER JOIN TableB AS b ON a.Column1 = b.Column1;
+------------+-----------+---------------------+ | a.Column1 | a.Column2 | b.Column1| b.Column3| +------------------------+---------------------+ | 1 | 2 | 1 | 3 | +------------+-----------+----------+----------+
The NATURAL JOIN of TableA and TableB on Column1 will return:
SELECT * FROM TableA NATURAL JOIN TableB +------------+----------+----------+ |Column1 | Column2 | Column3 | +-----------------------+----------+ | 1 | 2 | 3 | +------------+----------+----------+
Ref: https://bit.ly/3AG5CId
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