﻿ AdventureWorks: Evaluate whether the values in two columns are the same

# AdventureWorks Database: Evaluate whether the values in two columns are the same

## SQL Query - AdventureWorks: Exercise-129 with Solution

129. From the following table write a query in SQL to evaluate whether the values in the MakeFlag and FinishedGoodsFlag columns are the same.

Sample table: production.Product

Click to view Full table

Sample Solution:

``````SELECT ProductID, MakeFlag, FinishedGoodsFlag,
CASE
WHEN MakeFlag = FinishedGoodsFlag THEN NULL
ELSE MakeFlag
END
FROM Production.Product
WHERE ProductID < 10;
``````

Sample Output:

```productid|makeflag|finishedgoodsflag|makeflag|
---------+--------+-----------------+--------+
1|false   |false            |        |
2|false   |false            |        |
3|true    |false            |true    |
4|false   |false            |        |
```

## Practice Online

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.

﻿

## SQL: Tips of the Day

Difference between natural join and inner join

One significant difference between INNER JOIN and NATURAL JOIN is the number of columns returned-

Consider:

```TableA                           TableB
+------------+----------+        +--------------------+
|Column1     | Column2  |        |Column1  |  Column3 |
+-----------------------+        +--------------------+
| 1          |  2       |        | 1       |   3      |
+------------+----------+        +---------+----------+
```

The INNER JOIN of TableA and TableB on Column1 will return

```SELECT * FROM TableA AS a INNER JOIN TableB AS b USING (Column1);
SELECT * FROM TableA AS a INNER JOIN TableB AS b ON a.Column1 = b.Column1;
```
```+------------+-----------+---------------------+
| a.Column1  | a.Column2 | b.Column1| b.Column3|
+------------------------+---------------------+
| 1          |  2        | 1        |   3      |
+------------+-----------+----------+----------+
```

The NATURAL JOIN of TableA and TableB on Column1 will return:

```SELECT * FROM TableA NATURAL JOIN TableB
+------------+----------+----------+
|Column1     | Column2  | Column3  |
+-----------------------+----------+
| 1          |  2       |   3      |
+------------+----------+----------+
```

Ref: https://bit.ly/3AG5CId

We are closing our Disqus commenting system for some maintenanace issues. You may write to us at reach[at]yahoo[dot]com or visit us at Facebook