w3resource

AdventureWorks Database: Evaluate whether the values in two columns are the same

SQL Query - AdventureWorks: Exercise-129 with Solution

129. From the following table write a query in SQL to evaluate whether the values in the MakeFlag and FinishedGoodsFlag columns are the same.

Sample table: production.Product


Click to view Full table

Sample Solution:

SELECT ProductID, MakeFlag, FinishedGoodsFlag, 
   CASE  
       WHEN MakeFlag = FinishedGoodsFlag THEN NULL  
       ELSE MakeFlag  
   END  
FROM Production.Product  
WHERE ProductID < 10;

Sample Output:

productid|makeflag|finishedgoodsflag|makeflag|
---------+--------+-----------------+--------+
        1|false   |false            |        |
        2|false   |false            |        |
        3|true    |false            |true    |
        4|false   |false            |        |

SQL AdventureWorks Editor:

Practice Online


Contribute your code and comments through Disqus.

Previous: Change the display of product line categories with comment.
Next: Select data from first column that has a nonnull value.


What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.



Follow us on Facebook and Twitter for latest update.

SQL: Tips of the Day

Difference between natural join and inner join

One significant difference between INNER JOIN and NATURAL JOIN is the number of columns returned-

Consider:

TableA                           TableB
+------------+----------+        +--------------------+    
|Column1     | Column2  |        |Column1  |  Column3 |
+-----------------------+        +--------------------+
| 1          |  2       |        | 1       |   3      |
+------------+----------+        +---------+----------+

The INNER JOIN of TableA and TableB on Column1 will return

SELECT * FROM TableA AS a INNER JOIN TableB AS b USING (Column1);
SELECT * FROM TableA AS a INNER JOIN TableB AS b ON a.Column1 = b.Column1;
+------------+-----------+---------------------+    
| a.Column1  | a.Column2 | b.Column1| b.Column3|
+------------------------+---------------------+
| 1          |  2        | 1        |   3      |
+------------+-----------+----------+----------+

The NATURAL JOIN of TableA and TableB on Column1 will return:

SELECT * FROM TableA NATURAL JOIN TableB
+------------+----------+----------+    
|Column1     | Column2  | Column3  |
+-----------------------+----------+
| 1          |  2       |   3      |
+------------+----------+----------+

Ref: https://bit.ly/3AG5CId

 





We are closing our Disqus commenting system for some maintenanace issues. You may write to us at reach[at]yahoo[dot]com or visit us at Facebook