AdventureWorks Database: Contacts designated as a manager
SQL Query - AdventureWorks: Exercise-19 with Solution
19. From the following table write a query in SQL to find the contacts who are designated as a manager in various departments. Returns ContactTypeID, name. Sort the result set in descending order.
Sample table: Person.ContactType
Sample Solution:
SELECT ContactTypeID, Name
FROM Person.ContactType
WHERE Name LIKE '%Manager%'
ORDER BY Name DESC;
Sample Output:
contacttypeid|name |
-------------+-------------------------------+
19|Sales Manager |
15|Purchasing Manager |
13|Product Manager |
8|Marketing Manager |
6|International Marketing Manager|
1|Accounting Manager |
SQL AdventureWorks Editor:
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SQL: Tips of the Day
Difference between natural join and inner join
One significant difference between INNER JOIN and NATURAL JOIN is the number of columns returned-
Consider:
TableA TableB +------------+----------+ +--------------------+ |Column1 | Column2 | |Column1 | Column3 | +-----------------------+ +--------------------+ | 1 | 2 | | 1 | 3 | +------------+----------+ +---------+----------+
The INNER JOIN of TableA and TableB on Column1 will return
SELECT * FROM TableA AS a INNER JOIN TableB AS b USING (Column1); SELECT * FROM TableA AS a INNER JOIN TableB AS b ON a.Column1 = b.Column1;
+------------+-----------+---------------------+ | a.Column1 | a.Column2 | b.Column1| b.Column3| +------------------------+---------------------+ | 1 | 2 | 1 | 3 | +------------+-----------+----------+----------+
The NATURAL JOIN of TableA and TableB on Column1 will return:
SELECT * FROM TableA NATURAL JOIN TableB +------------+----------+----------+ |Column1 | Column2 | Column3 | +-----------------------+----------+ | 1 | 2 | 3 | +------------+----------+----------+
Ref: https://bit.ly/3AG5CId
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