AdventureWorks Database: Create a list of unique jobtitles

SQL Query - AdventureWorks: Exercise-6 with Solution

6. From the following table write a query in SQL to create a list of unique jobtitles in the employee table in Adventureworks database. Return jobtitle column and arranged the resultset in ascending order.

businessentityid|nationalidnumber|loginid                     |jobtitle                                |birthdate |maritalstatus|gender|hiredate  |salariedflag|vacationhours|sickleavehours|currentflag|rowguid                             |modifieddate           |organizationnode|
----------------+----------------+----------------------------+----------------------------------------+----------+-------------+------+----------+------------+-------------+--------------+-----------+------------------------------------+-----------------------+----------------+
               1|295847284       |adventure-works\ken0        |Chief Executive Officer                 |1969-01-29|S            |M     |2009-01-14|true        |           99|            69|true       |f01251e5-96a3-448d-981e-0f99d789110d|2014-06-30 00:00:00.000|/               |
               2|245797967       |adventure-works\terri0      |Vice President of Engineering           |1971-08-01|S            |F     |2008-01-31|true        |            1|            20|true       |45e8f437-670d-4409-93cb-f9424a40d6ee|2014-06-30 00:00:00.000|/1/             |
               3|509647174       |adventure-works\roberto0    |Engineering Manager                     |1974-11-12|M            |M     |2007-11-11|true        |            2|            21|true       |9bbbfb2c-efbb-4217-9ab7-f97689328841|2014-06-30 00:00:00.000|/1/1/           |
               4|112457891       |adventure-works\rob0        |Senior Tool Designer                    |1974-12-23|S            |M     |2007-12-05|false       |           48|            80|true       |59747955-87b8-443f-8ed4-f8ad3afdf3a9|2014-06-30 00:00:00.000|/1/1/1/         |
               5|695256908       |adventure-works\gail0       |Design Engineer                         |1952-09-27|M            |F     |2008-01-06|true        |            5|            22|true       |ec84ae09-f9b8-4a15-b4a9-6ccbab919b08|2014-06-30 00:00:00.000|/1/1/2/         |
               6|998320692       |adventure-works\jossef0     |Design Engineer                         |1959-03-11|M            |M     |2008-01-24|true        |            6|            23|true       |e39056f1-9cd5-478d-8945-14aca7fbdcdd|2014-06-30 00:00:00.000|/1/1/3/         |
               7|134969118       |adventure-works\dylan0      |Research and Development Manager        |1987-02-24|M            |M     |2009-02-08|true        |           61|            50|true       |4f46deca-ef01-41fd-9829-0adab368e431|2014-06-30 00:00:00.000|/1/1/4/         |
               8|811994146       |adventure-works\diane1      |Research and Development Engineer       |1986-06-05|S            |F     |2008-12-29|true        |           62|            51|true       |31112635-663b-4018-b4a2-a685c0bf48a4|2014-06-30 00:00:00.000|/1/1/4/1/       |
               9|658797903       |adventure-works\gigi0       |Research and Development Engineer       |1979-01-21|M            |F     |2009-01-16|true        |           63|            51|true       |50b6cdc6-7570-47ef-9570-48a64b5f2ecf|2014-06-30 00:00:00.000|/1/1/4/2/       |
              10|879342154       |adventure-works\michael6    |Research and Development Manager        |1984-11-30|M            |M     |2009-05-03|true        |           16|            64|true       |eaa43680-5571-40cb-ab1a-3bf68f04459e|2014-06-30 00:00:00.000|/1/1/4/3/       |
			  -- more --

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Sample Solution:

-- Selecting distinct values from the 'jobtitle' column of the 'employee' table in the 'humanresources' schema
SELECT DISTINCT jobtitle  
-- Ordering the result set alphabetically by the 'jobtitle' column
FROM humanresources.employee  
ORDER BY jobtitle;

Explanation:

• The SELECT DISTINCT jobtitle statement retrieves unique values from the 'jobtitle' column of the 'employee' table.
• FROM humanresources.employee specifies the table from which the data will be retrieved. 'humanresources' is the schema name and 'employee' is the table name.
• The ORDER BY jobtitle clause sorts the result set alphabetically by the 'jobtitle' column.

Sample Output:

jobtitle                                |
----------------------------------------+
Accountant                              |
Accounts Manager                        |
Accounts Payable Specialist             |
Accounts Receivable Specialist          |
Application Specialist                  |
Assistant to the Chief Financial Officer|
Benefits Specialist                     |
Buyer                                   |
Chief Executive Officer                 |
Chief Financial Officer                 |
Control Specialist                      |
Database Administrator                  |
Design Engineer                         |
Document Control Assistant              |
...

SQL AdventureWorks Editor:

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