w3resource

AdventureWorks Database: Return the five leftmost characters of each product name

SQL Query - AdventureWorks: Exercise-62 with Solution

62. From the following table write a query in SQL to return the five leftmost characters of each product name.

Sample table: production.product
productid|name                            |productnumber|makeflag|finishedgoodsflag|color       |safetystocklevel|reorderpoint|standardcost|listprice|size|sizeunitmeasurecode|weightunitmeasurecode|weight |daystomanufacture|productline|class|style|productsubcategoryid|productmodelid|sellstartdate          |sellenddate            |discontinueddate|rowguid                             |modifieddate           |
---------+--------------------------------+-------------+--------+-----------------+------------+----------------+------------+------------+---------+----+-------------------+---------------------+-------+-----------------+-----------+-----+-----+--------------------+--------------+-----------------------+-----------------------+----------------+------------------------------------+-----------------------+
        1|Adjustable Race                 |AR-5381      |false   |false            |            |            1000|         750|           0|        0|    |                   |                     |       |                0|           |     |     |                    |              |2008-04-30 00:00:00.000|                       |                |694215b7-08f7-4c0d-acb1-d734ba44c0c8|2014-02-08 10:01:36.827|
        2|Bearing Ball                    |BA-8327      |false   |false            |            |            1000|         750|           0|        0|    |                   |                     |       |                0|           |     |     |                    |              |2008-04-30 00:00:00.000|                       |                |58ae3c20-4f3a-4749-a7d4-d568806cc537|2014-02-08 10:01:36.827|
        3|BB Ball Bearing                 |BE-2349      |true    |false            |            |             800|         600|           0|        0|    |                   |                     |       |                1|           |     |     |                    |              |2008-04-30 00:00:00.000|                       |                |9c21aed2-5bfa-4f18-bcb8-f11638dc2e4e|2014-02-08 10:01:36.827|
        4|Headset Ball Bearings           |BE-2908      |false   |false            |            |             800|         600|           0|        0|    |                   |                     |       |                0|           |     |     |                    |              |2008-04-30 00:00:00.000|                       |                |ecfed6cb-51ff-49b5-b06c-7d8ac834db8b|2014-02-08 10:01:36.827|
      316|Blade                           |BL-2036      |true    |false            |            |             800|         600|           0|        0|    |                   |                     |       |                1|           |     |     |                    |              |2008-04-30 00:00:00.000|                       |                |e73e9750-603b-4131-89f5-3dd15ed5ff80|2014-02-08 10:01:36.827|
      317|LL Crankarm                     |CA-5965      |false   |false            |Black       |             500|         375|           0|        0|    |                   |                     |       |                0|           |L    |     |                    |              |2008-04-30 00:00:00.000|                       |                |3c9d10b7-a6b2-4774-9963-c19dcee72fea|2014-02-08 10:01:36.827|
      318|ML Crankarm                     |CA-6738      |false   |false            |Black       |             500|         375|           0|        0|    |                   |                     |       |                0|           |M    |     |                    |              |2008-04-30 00:00:00.000|                       |                |eabb9a92-fa07-4eab-8955-f0517b4a4ca7|2014-02-08 10:01:36.827|
	  -- more --

Click to view Full table

Sample Solution:

-- Selecting the leftmost 5 characters of the 'Name' column
SELECT LEFT(Name, 5)   
-- From the Production schema's Product table
FROM Production.Product  
-- Ordering the result set by the 'ProductID' column
ORDER BY ProductID;

Explanation:

  • The SQL query retrieves data from the Product table within the Production schema.
  • It uses the LEFT() function to extract the leftmost 5 characters of the Name column.
  • The LEFT() function is used to return a specified number of characters from the left side of a string.
  • The result set is ordered by the ProductID column.

Sample Output:

left |
-----+
Adjus|
Beari|
BB Ba|
Heads|
Blade|
LL Cr|
ML Cr|
HL Cr|
Chain|
Chain|
Chain|
...

SQL AdventureWorks Editor:

Practice Online


Contribute your code and comments through Disqus.

Previous: Concatenate the columns separated by a unique character.
Next: Find the number of characters in the FirstName column.

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.



Follow us on Facebook and Twitter for latest update.