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AdventureWorks Database: Return the five leftmost characters of each product name

SQL Query - AdventureWorks: Exercise-62 with Solution

62. From the following table write a query in SQL to return the five leftmost characters of each product name.

Sample table: production.product
productid|name                            |productnumber|makeflag|finishedgoodsflag|color       |safetystocklevel|reorderpoint|standardcost|listprice|size|sizeunitmeasurecode|weightunitmeasurecode|weight |daystomanufacture|productline|class|style|productsubcategoryid|productmodelid|sellstartdate          |sellenddate            |discontinueddate|rowguid                             |modifieddate           |
---------+--------------------------------+-------------+--------+-----------------+------------+----------------+------------+------------+---------+----+-------------------+---------------------+-------+-----------------+-----------+-----+-----+--------------------+--------------+-----------------------+-----------------------+----------------+------------------------------------+-----------------------+
        1|Adjustable Race                 |AR-5381      |false   |false            |            |            1000|         750|           0|        0|    |                   |                     |       |                0|           |     |     |                    |              |2008-04-30 00:00:00.000|                       |                |694215b7-08f7-4c0d-acb1-d734ba44c0c8|2014-02-08 10:01:36.827|
        2|Bearing Ball                    |BA-8327      |false   |false            |            |            1000|         750|           0|        0|    |                   |                     |       |                0|           |     |     |                    |              |2008-04-30 00:00:00.000|                       |                |58ae3c20-4f3a-4749-a7d4-d568806cc537|2014-02-08 10:01:36.827|
        3|BB Ball Bearing                 |BE-2349      |true    |false            |            |             800|         600|           0|        0|    |                   |                     |       |                1|           |     |     |                    |              |2008-04-30 00:00:00.000|                       |                |9c21aed2-5bfa-4f18-bcb8-f11638dc2e4e|2014-02-08 10:01:36.827|
        4|Headset Ball Bearings           |BE-2908      |false   |false            |            |             800|         600|           0|        0|    |                   |                     |       |                0|           |     |     |                    |              |2008-04-30 00:00:00.000|                       |                |ecfed6cb-51ff-49b5-b06c-7d8ac834db8b|2014-02-08 10:01:36.827|
      316|Blade                           |BL-2036      |true    |false            |            |             800|         600|           0|        0|    |                   |                     |       |                1|           |     |     |                    |              |2008-04-30 00:00:00.000|                       |                |e73e9750-603b-4131-89f5-3dd15ed5ff80|2014-02-08 10:01:36.827|
      317|LL Crankarm                     |CA-5965      |false   |false            |Black       |             500|         375|           0|        0|    |                   |                     |       |                0|           |L    |     |                    |              |2008-04-30 00:00:00.000|                       |                |3c9d10b7-a6b2-4774-9963-c19dcee72fea|2014-02-08 10:01:36.827|
      318|ML Crankarm                     |CA-6738      |false   |false            |Black       |             500|         375|           0|        0|    |                   |                     |       |                0|           |M    |     |                    |              |2008-04-30 00:00:00.000|                       |                |eabb9a92-fa07-4eab-8955-f0517b4a4ca7|2014-02-08 10:01:36.827|
	  -- more --

Click to view Full table

Sample Solution:

-- Selecting the leftmost 5 characters of the 'Name' column
SELECT LEFT(Name, 5)   
-- From the Production schema's Product table
FROM Production.Product  
-- Ordering the result set by the 'ProductID' column
ORDER BY ProductID;

Explanation:

  • The SQL query retrieves data from the Product table within the Production schema.
  • It uses the LEFT() function to extract the leftmost 5 characters of the Name column.
  • The LEFT() function is used to return a specified number of characters from the left side of a string.
  • The result set is ordered by the ProductID column.

Sample Output:

left |
-----+
Adjus|
Beari|
BB Ba|
Heads|
Blade|
LL Cr|
ML Cr|
HL Cr|
Chain|
Chain|
Chain|
...

SQL AdventureWorks Editor:

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Previous: Concatenate the columns separated by a unique character.
Next: Find the number of characters in the FirstName column.

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