SQL Challenges-1: Combine two tables

SQL Challenges-1: Exercise-1 with Solution

From the following tables, write a SQL query to find the information on each salesperson of ABC Company. Return name, city, country and state of each salesperson.

Input:

Table: salespersons

Structure:

Data:

Table : address

Sturucture:

Data:

Sample Solution:

SQL Code(MySQL:

CREATE TABLE IF NOT EXISTS salespersons(salesperson_id int, first_name varchar(255), last_name varchar(255));
CREATE TABLE IF NOT EXISTS address (address_id int, salesperson_id  int, city varchar(255), state varchar(255), country varchar(255));
TRUNCATE TABLE address;
INSERT INTO salespersons (salesperson_id, first_name, last_name) VALUES ('1', 'Green', 'Wright');
INSERT INTO salespersons (salesperson_id, first_name, last_name) VALUES ('2', 'Jones', 'Collins');
INSERT INTO salespersons (salesperson_id, first_name, last_name) VALUES ('3', 'Bryant', 'Davis');

TRUNCATE TABLE address;
INSERT INTO address (address_id, salesperson_id, city, state, country) VALUES ('1', '2', 'Los Angeles','California', 'USA');
INSERT INTO address (address_id, salesperson_id, city, state, country) VALUES ('2', '3', 'Denver', 'Colorado','USA');
INSERT INTO address (address_id, salesperson_id, city, state, country) VALUES ('3', '4', 'Atlanta', 'Georgia','USA');

select * from address;
select * from salespersons;

SELECT first_name, last_name, city, state 
FROM salespersons LEFT JOIN address
ON salespersons.salesperson_id = address.salesperson_id;

Sample Output:

first_name|last_name|city       |state     |
----------|---------|-----------|----------|
Jones     |Collins  |Los Angeles|California|
Bryant    |Davis    |Denver     |Colorado  |
Green     |Wright   |           |          |

SQL Code Editor:

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