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SQL Challenges-1: Find the first login date for each customer

SQL Challenges-1: Exercise-25 with Solution

From the following table, write a SQL query to find the first login date for each customer. Return customer id, login date.

Input:

Table: bank_trans

Structure:

FieldTypeNullKeyDefaultExtra
trans_idint(11)YES
customer_idint(11)YES
login_datedateYES

Data:

trans_idcustomer_idlogin_date
10130022019-09-01
10130022019-08-01
10230032018-09-13
10230022018-07-24
10330012019-09-25
10230042017-09-05

Sample Solution:

SQL Code(MySQL):

DROP TABLE IF EXISTS bank_trans;
CREATE TABLE bank_trans(trans_id int, customer_id int, login_date date);
INSERT INTO bank_trans VALUES (101, 3002, '2019-09-01');
INSERT INTO bank_trans VALUES (101, 3002, '2019-08-01');
INSERT INTO bank_trans VALUES (102, 3003, '2018-09-13');
INSERT INTO bank_trans VALUES (102, 3002, '2018-07-24');
INSERT INTO bank_trans VALUES (103, 3001, '2019-09-25');
INSERT INTO bank_trans VALUES (102, 3004, '2017-09-05');
SELECT * FROM bank_trans;

SELECT customer_id, MIN(login_date) first_login
FROM bank_trans
GROUP BY customer_id;

Sample Output:

customer_id|first_login|
-----------|-----------|
       3001| 2019-09-25|
       3002| 2018-07-24|
       3003| 2018-09-13|
       3004| 2017-09-05|

SQL Code Editor:


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SQL: Tips of the Day

A table name as a variable -

For static queries, like the one in your question, table names and column names need to be static.

For dynamic queries, you should generate the full SQL dynamically, and use sp_executesql to execute it.

Static query:

SELECT * FROM [DB_ONE].[dbo].[ACTY]
EXCEPT
SELECT * FROM [DB_TWO].[dbo].[ACTY]

Ref: https://bit.ly/3sFxxnk

 





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