﻿ SQL Challenges-1: Nth Highest Sale amount - w3resource

# SQL Challenges-1: Nth Highest Sale amount

## SQL Challenges-1: Exercise-3 with Solution

From the following table, write a SQL query to find the Nth highest sale. Return sale amount.

Input:

Table: salesemast

Structure:

FieldTypeNullKeyDefaultExtra
sale_idint(11)YES
employee_idint(11)YES
sale_datedateYES
sale_amtint(11)YES

Data:

sale_idemployee_idsale_datesale_amt
110002012-03-084500
210012012-03-095500
310032012-04-103500

Sample Solution:

SQL Code(MySQL):

``````CREATE TABLE IF NOT EXISTS salemast(sale_id int, employee_id int, sale_date date, sale_amt int);
TRUNCATE TABLE salemast;
INSERT INTO salemast (sale_id, employee_id, sale_date, sale_amt) VALUES ('1', '1000', '2012-03-08', 4500);
INSERT INTO salemast (sale_id, employee_id, sale_date, sale_amt) VALUES ('2', '1001', '2012-03-09', 5500);
INSERT INTO salemast (sale_id, employee_id, sale_date, sale_amt) VALUES ('3', '1003', '2012-04-10', 3500);
SELECT * FROM salemast;
```
```

Sample Output:

```getNthHighestSaleAmt(3)|
-----------------------|
3500|
```

Solution-1:

``````# Solution
USE ‘temp';
DROP function IF EXISTS 'getNthHighestSaleAmt';
DELIMITER \$\$
USE 'temp'\$\$
# -------------------------------
CREATE FUNCTION 'getNthHighestSaleAmt' (N INT) RETURNS int(11)
BEGIN
SET N = N-1;
RETURN (
SELECT DISTINCT sale_amt FROM salemast
ORDER BY sale_amt DESC
LIMIT 1 OFFSET N
);
END\$\$
DELIMITER ;
# To Execute the function:
SELECT getNthHighestSaleAmt(3);
``````

SQL Code Editor:

Previous: Third Highest Sale.
Next: Consecutive Numbers.

﻿

## SQL: Tips of the Day

How to select the nth row in a SQL database table?

Basically, PostgreSQL and MySQL supports the non-standard:

```SELECT...
LIMIT y OFFSET x
```

Oracle, DB2 and MSSQL supports the standard windowing functions:

```SELECT * FROM (
SELECT
ROW_NUMBER() OVER (ORDER BY key ASC) AS rownumber,
columns
FROM tablename
) AS foo
WHERE rownumber <= n
```

Database: SQL

Ref: https://bit.ly/3zPxcD8