SQL Challenges-1: All People Report to the Given Manager
SQL Challenges-1: Exercise-45 with Solution
From the following table write a SQL query to find all employees that directly or indirectly report to the head of the company. Return employee_id, name, and manager_id.
Input:
Table: emp_test_table
Structure:
Field | Type | Null | Key | Default | Extra |
---|---|---|---|---|---|
employee_id | int(11) | NO | PRI | ||
first_name | varchar(25) | YES | |||
manager_id | int(11) | YES |
Data:
employee_id | first_name | manager_id |
---|---|---|
100 | Steven | 100 |
101 | Neena | 100 |
102 | Lex | 100 |
103 | Alexander | 102 |
104 | Bruce | 103 |
105 | David | 103 |
106 | Valli | 103 |
107 | Diana | 103 |
108 | Nancy | 101 |
109 | Daniel | 108 |
110 | John | 108 |
Sample Solution:
SQL Code(MySQL):
CREATE TABLE emp_test_table (
employee_id integer NOT NULL UNIQUE,
first_name varchar(25),
manager_id integer);
insert into emp_test_table values(100,'Steven ',100);
insert into emp_test_table values(101,'Neena ',100);
insert into emp_test_table values(102,'Lex ',100);
insert into emp_test_table values(103,'Alexander ',102);
insert into emp_test_table values(104,'Bruce ',103);
insert into emp_test_table values(105,'David ',103);
insert into emp_test_table values(106,'Valli ',103);
insert into emp_test_table values(107,'Diana ',103);
insert into emp_test_table values(108,'Nancy ',101);
insert into emp_test_table values(109,'Daniel ',108);
insert into emp_test_table values(110,'John ',108);
SELECT employee_id,first_name as Name, manager_id
FROM emp_test_table
WHERE manager_id in (SELECT employee_id from emp_test_table
WHERE manager_id in (SELECT employee_id from emp_test_table WHERE manager_id = 100))
AND employee_id != 100;
Sample Output:
employee_id|Name |manager_id| -----------|-----------|----------| 101|Neena | 100| 102|Lex | 100| 103|Alexander | 102| 104|Bruce | 103| 105|David | 103| 106|Valli | 103| 107|Diana | 103| 108|Nancy | 101| 109|Daniel | 108| 110|John | 108|
SQL Code Editor:
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