SQL Challenges-1: Find the Team Size
SQL Challenges-1: Exercise-47 with Solution
From the following table write a SQL query to find the number of employees are working in the department of each employees. Return employee Id and number of employees are working in their department.
Input:
Table: emp_test_table
Structure:
Field | Type | Null | Key | Default | Extra |
---|---|---|---|---|---|
employee_id | int(11) | NO | PRI | ||
first_name | varchar(25) | YES | |||
department_id | int(11) | YES |
Data:
employee_id | first_name | department_id |
---|---|---|
100 | Steven | 90 |
101 | Neena | 90 |
102 | Lex | 90 |
103 | Alexander | 60 |
104 | Bruce | 60 |
105 | David | 60 |
106 | Valli | 60 |
107 | Diana | 60 |
108 | Nancy | 100 |
109 | Daniel | 100 |
110 | John | 100 |
Sample Solution:
SQL Code(MySQL):
CREATE TABLE emp_test_table (
employee_id integer NOT NULL UNIQUE,
first_name varchar(25),
department_id integer);
insert into emp_test_table values(100,'Steven ',90);
insert into emp_test_table values(101,'Neena ',90);
insert into emp_test_table values(102,'Lex ',90);
insert into emp_test_table values(103,'Alexander ',60);
insert into emp_test_table values(104,'Bruce ',60);
insert into emp_test_table values(105,'David ',60);
insert into emp_test_table values(106,'Valli ',60);
insert into emp_test_table values(107,'Diana ',60);
insert into emp_test_table values(108,'Nancy ',100);
insert into emp_test_table values(109,'Daniel ',100);
insert into emp_test_table values(110,'John ',100);
SELECT em1.employee_id, COUNT(em1.department_id) AS employees_in_department
FROM emp_test_table em1
JOIN emp_test_table em2
ON em1.department_id=em2.department_id
GROUP BY em1.employee_id;
Sample Output:
employee_id|employees_in_department| -----------|-----------------------| 100| 3| 101| 3| 102| 3| 103| 5| 104| 5| 105| 5| 106| 5| 107| 5| 108| 3| 109| 3| 110| 3|
SQL Code Editor:
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