SQL Exercise: List the names of those employees starting with A
SQL employee Database: Exercise-105 with Solution
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105. From the following table, write a SQL query to identify those employees whose names begin with 'A' and are six characters long. Return employee name.
Sample table: employees
SELECT emp_name FROM employees WHERE emp_name LIKE 'A%' AND length(emp_name)=6;
emp_name ---------- ADELYN ADNRES (2 rows)
The said query in SQL that selects the names of employees whose names start with 'A' and have a length of exactly 6 characters from the employees table.
The WHERE clause includes employees whose names starts with 'A' and the length() function to check if the length of the name is exactly 6 characters.
Sample Database: employee
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Previous SQL Exercise: List the number of employees and average salary.
Next SQL Exercise: Six-character employee names with R in 3rd position.
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SQL: Tips of the Day
Grouped LIMIT in PostgreSQL: Show the first N rows for each group?
db=# SELECT * FROM xxx; id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 3 | 1 | C 4 | 1 | D 5 | 2 | E 6 | 2 | F 7 | 3 | G 8 | 2 | H (8 rows)
I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 5 | 2 | E 6 | 2 | F 7 | 3 | G (5 rows)
PostgreSQL v9.3 you can do a lateral join
select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer join lateral ( select * from t t_inner where t_inner.section_id = t_outer.section_id order by t_inner.name limit 2 ) t_top on true order by t_outer.section_id;
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