SQL Exercise: Employees joined with a as the 2nd character of a month

SQL employee Database: Exercise-108 with Solution

[An editor is available at the bottom of the page to write and execute the scripts.]

108. From the following table, write a SQL query to find those employees who joined in the month of where the second letter is 'a'. Return number of employees.

Sample table: employees

Sample Solution:

FROM employees
WHERE to_char(hire_date,'mon') LIKE '_a%';

Sample Output:

 emp_id | emp_name | job_name | manager_id | hire_date  | salary  | commission | dep_id
  66928 | BLAZE    | MANAGER  |      68319 | 1991-05-01 | 2750.00 |            |   3001
  68736 | ADNRES   | CLERK    |      67858 | 1997-05-23 | 1200.00 |            |   2001
  69324 | MARKER   | CLERK    |      67832 | 1992-01-23 | 1400.00 |            |   1001
(3 rows)


The given query in SQL that selects all the columns and rows from the table 'employees' where the hire date has a month that starts with the letter "a".

The function TO_CHAR() converts the date in the "hire_date" column to a string representation of the month, and the LIKE operator with the pattern 'a%' matches any string that has a second character that is the letter "a". The underscore () represents any single character.

Practice Online

Sample Database: employee

employee database structure

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous SQL Exercise: Employee start with 'A' and end with 'N', length six.
Next SQL Exercise: List the employees whose names contain AR together.

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.

Follow us on Facebook and Twitter for latest update.