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SQL Exercise: List the employees whose ID not starting with digit 68

SQL employee Database: Exercise-111 with Solution

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111. From the following table, write a SQL query to find those employees whose ID not start with the digit 68. Return employee ID, employee ID using trim function.

Sample table: employees


Sample Solution:

SELECT emp_id,
       trim(to_char(emp_id,'99999'))
FROM employees
WHERE trim(to_char(emp_id,'99999')) NOT LIKE '68%';

Sample Output:

 emp_id | btrim
--------+-------
  66928 | 66928
  67832 | 67832
  65646 | 65646
  67858 | 67858
  69062 | 69062
  63679 | 63679
  64989 | 64989
  65271 | 65271
  66564 | 66564
  69000 | 69000
  69324 | 69324
(11 rows)

Explanation:

The said query in SQL that return all "emp_id" values with leading zeros, except those that start with "68".

The "trim" function removes any leading or trailing spaces from the resulting string.

The query filters out any rows where the "emp_id" starts with the characters "68" using the "NOT LIKE" operator.

Practice Online


Sample Database: employee

employee database structure

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Previous SQL Exercise: List the employees those who joined in 90's.
Next SQL Exercise: List the employees whose names containing the letter A.

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SQL: Tips of the Day

Grouped LIMIT in PostgreSQL: Show the first N rows for each group?

db=# SELECT * FROM xxx;
 id | section_id | name
----+------------+------
  1 |          1 | A
  2 |          1 | B
  3 |          1 | C
  4 |          1 | D
  5 |          2 | E
  6 |          2 | F
  7 |          3 | G
  8 |          2 | H
(8 rows)

I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:

id | section_id | name
----+------------+------
  1 |          1 | A
  2 |          1 | B
  5 |          2 | E
  6 |          2 | F
  7 |          3 | G
(5 rows)

PostgreSQL v9.3 you can do a lateral join

select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer
join lateral (
    select * from t t_inner
    where t_inner.section_id = t_outer.section_id
    order by t_inner.name
    limit 2
) t_top on true
order by t_outer.section_id;

Database: PostgreSQL

Ref: https://bit.ly/3AfYwZI

 

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