SQL Exercise: Employees who joined in a month having 2nd char is A

SQL employee Database: Exercise-115 with Solution

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115. From the following table, write a SQL query to find those employees who joined in any month, but the name of the month contain the character ‘A’ in second position. Return complete information about the employees.

Sample table: employees

Sample Solution:

SELECT *
FROM employees
WHERE to_char(hire_date,'MON') LIKE '_A%';

Sample Output:

 emp_id | emp_name | job_name | manager_id | hire_date  | salary  | commission | dep_id
--------+----------+----------+------------+------------+---------+------------+--------
  66928 | BLAZE    | MANAGER  |      68319 | 1991-05-01 | 2750.00 |            |   3001
  68736 | ADNRES   | CLERK    |      67858 | 1997-05-23 | 1200.00 |            |   2001
  69324 | MARKER   | CLERK    |      67832 | 1992-01-23 | 1400.00 |            |   1001
(3 rows)

Explanation:

The said query in SQL that returns all rows from the 'employees' table where the second letter of the "hire_date" month is "A", and the month name is three characters long. The "to_char" function converts the "hire_date" column to a string in the format "MON", which returns the abbreviated name of the month.

The underscore "_" symbol is used as a wildcard to match any single character before the "A" character.

Practice Online

Sample Database: employee

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