SQL Exercise: Find the salaries of all employees
SQL employee Database: Exercise-2 with Solution
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2. From the following table, write a SQL query to find the salaries of all employees. Return salary.
Sample table: employees
SELECT salary FROM employees;
salary --------- 6000.00 2750.00 2550.00 2957.00 3100.00 3100.00 900.00 1700.00 1350.00 1350.00 1600.00 1200.00 1050.00 1400.00 (14 rows)
The said query in SQL that retrieves only the "salary" column from the 'employees' table.
The query returns a result set that includes all the values stored in the "salary" column for all rows of the 'employees' table.
Relational Algebra Expression:
Relational Algebra Tree:
Sample Database: employee
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Previous SQL Exercise: Display all the information of the employees.
Next SQL Exercise: Display the unique designations for the employees.
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SQL: Tips of the Day
Grouped LIMIT in PostgreSQL: Show the first N rows for each group?
db=# SELECT * FROM xxx; id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 3 | 1 | C 4 | 1 | D 5 | 2 | E 6 | 2 | F 7 | 3 | G 8 | 2 | H (8 rows)
I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 5 | 2 | E 6 | 2 | F 7 | 3 | G (5 rows)
PostgreSQL v9.3 you can do a lateral join
select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer join lateral ( select * from t t_inner where t_inner.section_id = t_outer.section_id order by t_inner.name limit 2 ) t_top on true order by t_outer.section_id;
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