SQL Exercise: Employee names and salaries are increased by 15% in $
SQL employee Database: Exercise-4 with Solution
[An editor is available at the bottom of the page to write and execute the scripts.]
4. From the following table, write a SQL query to list the employees’ name, increased their salary by 15%, and expressed as number of Dollars.
Sample table: employees
SELECT emp_name, to_char(1.15*salary,'$99,999') AS "Salary" FROM employees;
emp_name | Salary ----------+---------- KAYLING | $ 6,900 BLAZE | $ 3,163 CLARE | $ 2,933 JONAS | $ 3,401 SCARLET | $ 3,565 FRANK | $ 3,565 SANDRINE | $ 1,035 ADELYN | $ 1,955 WADE | $ 1,553 MADDEN | $ 1,553 TUCKER | $ 1,840 ADNRES | $ 1,380 JULIUS | $ 1,208 MARKER | $ 1,610 (14 rows)
The provided query in SQL that retrieves names of all the employees, and their corresponding salaries, adjusted by a 15% increase aliased as "Salary". The AS keyword is used to assign the name "Salary" to the newly created column.
Sample Database: employee
Have another way to solve this solution? Contribute your code (and comments) through Disqus.
Previous SQL Exercise: Display the unique designations for the employees.
Next SQL Exercise: Produce the output of employees name and job name.
What is the difficulty level of this exercise?
Test your Programming skills with w3resource's quiz.
SQL: Tips of the Day
Grouped LIMIT in PostgreSQL: Show the first N rows for each group?
db=# SELECT * FROM xxx; id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 3 | 1 | C 4 | 1 | D 5 | 2 | E 6 | 2 | F 7 | 3 | G 8 | 2 | H (8 rows)
I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 5 | 2 | E 6 | 2 | F 7 | 3 | G (5 rows)
PostgreSQL v9.3 you can do a lateral join
select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer join lateral ( select * from t t_inner where t_inner.section_id = t_outer.section_id order by t_inner.name limit 2 ) t_top on true order by t_outer.section_id;
- Weekly Trends
- Python Interview Questions and Answers: Comprehensive Guide
- Scala Exercises, Practice, Solution
- Kotlin Exercises practice with solution
- MongoDB Exercises, Practice, Solution
- SQL Exercises, Practice, Solution - JOINS
- Java Basic Programming Exercises
- SQL Subqueries
- Adventureworks Database Exercises
- C# Sharp Basic Exercises
- SQL COUNT() with distinct
- Java Collection Exercises
- SQL COUNT() function
- SQL Inner Join
We are closing our Disqus commenting system for some maintenanace issues. You may write to us at reach[at]yahoo[dot]com or visit us at Facebook