SQL Exercise: List the employees working under various managers
SQL employee Database: Exercise-46 with Solution
[An editor is available at the bottom of the page to write and execute the scripts.]
46. From the following table, write a SQL query to find out which employees are working under the managers 63679, 68319, 66564, or 69000. Return complete information about the employees.
Sample table: employees
Pictorial Presentation:
Sample Solution:
SELECT *
FROM employees
WHERE manager_id IN (63679,
68319,
66564,
69000);
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 (3 rows)
Explanation:
The said query in SQL that selects all columns from the 'employees' table where the "manager_id" column has a value that matches any of the four values provided in the "IN" clause. The values in the "IN" clause are 63679, 68319, 66564, and 69000 represents manager IDs in the 'employees' table.
Relational Algebra Expression:
Relational Algebra Tree:
Practice Online
Sample Database: employee
Have another way to solve this solution? Contribute your code (and comments) through Disqus.
Previous SQL Exercise: Employees who joined on the given days in the year 1991.
Next SQL Exercise: Employees who joined after the month of JUNE in 1991.
What is the difficulty level of this exercise?
Test your Programming skills with w3resource's quiz.
It will be nice if you may share this link in any developer community or anywhere else, from where other developers may find this content. Thanks.
https://www.w3resource.com/sql-exercises/employee-database-exercise/sql-employee-database-exercise-46.php
- Weekly Trends and Language Statistics
- Weekly Trends and Language Statistics