﻿ SQL exercises on employee Database: List the employees who joined in 90's - w3resource

# SQL exercises on employee Database: List the employees who joined in 90's

## SQL employee Database: Exercise-48 with Solution

[An editor is available at the bottom of the page to write and execute the scripts.]

48. From the following table, write a SQL query to find those employees who joined in 90's. Return complete information about the employees.

Sample table: employees

Pictorial Presentation:

Sample Solution:

SELECT *
FROM employees
WHERE to_char(hire_date,'YY') BETWEEN '90' AND '99';

OR

SELECT *
FROM employees
WHERE to_char(hire_date,'YY') >= '90'
AND to_char(hire_date,'YY') < '99';

Sample Output:

emp_id | emp_name | job_name  | manager_id | hire_date  | salary  | commission | dep_id
--------+----------+-----------+------------+------------+---------+------------+--------
68319 | KAYLING  | PRESIDENT |            | 1991-11-18 | 6000.00 |            |   1001
66928 | BLAZE    | MANAGER   |      68319 | 1991-05-01 | 2750.00 |            |   3001
67832 | CLARE    | MANAGER   |      68319 | 1991-06-09 | 2550.00 |            |   1001
65646 | JONAS    | MANAGER   |      68319 | 1991-04-02 | 2957.00 |            |   2001
67858 | SCARLET  | ANALYST   |      65646 | 1997-04-19 | 3100.00 |            |   2001
69062 | FRANK    | ANALYST   |      65646 | 1991-12-03 | 3100.00 |            |   2001
63679 | SANDRINE | CLERK     |      69062 | 1990-12-18 |  900.00 |            |   2001
64989 | ADELYN   | SALESMAN  |      66928 | 1991-02-20 | 1700.00 |     400.00 |   3001
65271 | WADE     | SALESMAN  |      66928 | 1991-02-22 | 1350.00 |     600.00 |   3001
66564 | MADDEN   | SALESMAN  |      66928 | 1991-09-28 | 1350.00 |    1500.00 |   3001
68454 | TUCKER   | SALESMAN  |      66928 | 1991-09-08 | 1600.00 |       0.00 |   3001
68736 | ADNRES   | CLERK     |      67858 | 1997-05-23 | 1200.00 |            |   2001
69000 | JULIUS   | CLERK     |      66928 | 1991-12-03 | 1050.00 |            |   3001
69324 | MARKER   | CLERK     |      67832 | 1992-01-23 | 1400.00 |            |   1001
(14 rows)

## Practice Online

Sample Database: employee

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.

﻿

## SQL: Tips of the Day

MYSQL OR vs IN performance:

In many database servers, IN() is just a synonym for multiple OR clauses, because the two are logically equivalent. Not so in MySQL, which sorts the values in the IN() list and uses a fast binary search to see whether a value is in the list. This is O(Log n) in the size of the list, whereas an equivalent series of OR clauses is O(n) in the size of the list (i.e., much slower for large lists)

Ref: https://bit.ly/3PzLY69