SQL Exercise: Employees whose salary is greater than their managers
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54. From the following table, write a SQL query to identify employees whose salaries are higher than their managers' salaries. Return employee name, job name, manager ID, salary, manager name, manager's salary.
Sample table: employees
+-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+ | EMPLOYEE_ID | FIRST_NAME | LAST_NAME | EMAIL | PHONE_NUMBER | HIRE_DATE | JOB_ID | SALARY | COMMISSION_PCT | MANAGER_ID | DEPARTMENT_ID | +-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+ | 100 | Steven | King | SKING | 515.123.4567 | 2003-06-17 | AD_PRES | 24000.00 | 0.00 | 0 | 90 | | 101 | Neena | Kochhar | NKOCHHAR | 515.123.4568 | 2005-09-21 | AD_VP | 17000.00 | 0.00 | 100 | 90 | | 102 | Lex | De Haan | LDEHAAN | 515.123.4569 | 2001-01-13 | AD_VP | 17000.00 | 0.00 | 100 | 90 | | 103 | Alexander | Hunold | AHUNOLD | 590.423.4567 | 2006-01-03 | IT_PROG | 9000.00 | 0.00 | 102 | 60 | | 104 | Bruce | Ernst | BERNST | 590.423.4568 | 2007-05-21 | IT_PROG | 6000.00 | 0.00 | 103 | 60 | | 105 | David | Austin | DAUSTIN | 590.423.4569 | 2005-06-25 | IT_PROG | 4800.00 | 0.00 | 103 | 60 | | 106 | Valli | Pataballa | VPATABAL | 590.423.4560 | 2006-02-05 | IT_PROG | 4800.00 | 0.00 | 103 | 60 | | 107 | Diana | Lorentz | DLORENTZ | 590.423.5567 | 2007-02-07 | IT_PROG | 4200.00 | 0.00 | 103 | 60 | | 108 | Nancy | Greenberg | NGREENBE | 515.124.4569 | 2002-08-17 | FI_MGR | 12008.00 | 0.00 | 101 | 100 | | 109 | Daniel | Faviet | DFAVIET | 515.124.4169 | 2002-08-16 | FI_ACCOUNT | 9000.00 | 0.00 | 108 | 100 | ......... | 206 | William | Gietz | WGIETZ | 515.123.8181 | 2002-06-07 | AC_ACCOUNT | 8300.00 | 0.00 | 205 | 110 | +-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+
Pictorial Presentation:
Sample Solution:
SELECT w.emp_name,
w.job_name,
w.manager_id,
w.salary,
m.emp_name "Manager",
m.emp_id,
m.salary "Manager_Salary"
FROM employees w,
employees m
WHERE w.manager_id = m.emp_id
AND w.salary > m.salary;
Sample Output:
emp_name | job_name | manager_id | salary | Manager | emp_id | Manager_Salary ----------+----------+------------+---------+---------+--------+---------------- SCARLET | ANALYST | 65646 | 3100.00 | JONAS | 65646 | 2957.00 FRANK | ANALYST | 65646 | 3100.00 | JONAS | 65646 | 2957.00 (2 rows)
Explanation:
The given query in SQL that selects the employee name, job name, manager ID, salary, manager name aliased as "Manager", manager ID, and manager salary aliased as "Manager_Salary" for all employees from the employees table.
The query is using a self-join to combine data from the employees table with itself based on the manager_id column.
The WHERE clause filters those employees whose salary is greater than their manager's salary.
Go to:
PREV : Employees earning 60000 or not working as analysts.
NEXT : Employees whose salary is in a range and location PERTH.
Practice Online
Sample Database: employees
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