﻿ SQL: Salary of FRANK if his salary is equal to max_sal

# SQL Exercise: Salary of FRANK if his salary is equal to max_sal

## SQL employee Database: Exercise-58 with Solution

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58. From the following table, write a SQL query to find the name and salary of the employee FRANK. Salary should be equal to the maximum salary within his or her salary group.

Sample table: employees

Pictorial Presentation:

Sample Solution:

``````SELECT e.emp_name,
e.salary
FROM employees e,
WHERE e.emp_name = 'FRANK'
AND e.salary BETWEEN s.min_sal AND s.max_sal
AND e.salary = s.max_sal ;
``````

Sample Output:

``` emp_name | salary
----------+---------
FRANK    | 3100.00
(1 row)
```

Explanation:

The said query in SQL that selects the name and salary of an employee named 'FRANK' whose salary falls within a salary grade range, and whose salary is equal to the maximum salary of that salary grade.

The "WHERE" clause restricts the results to employees whose name is 'FRANK' and whose salary falls within a salary grade range by using the "BETWEEN" operator to compare the employee's salary to the minimum and maximum salaries of the salary grade.

The query then filters the results to employees whose salary is equal to the maximum salary of the salary grade.

## Practice Online

Sample Database: employee

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Previous SQL Exercise: List the employees whose manager name is JONAS.
Next SQL Exercise: Analysts or managers with a salary range, no commission.

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## SQL: Tips of the Day

Grouped LIMIT in PostgreSQL: Show the first N rows for each group?

```db=# SELECT * FROM xxx;
id | section_id | name
----+------------+------
1 |          1 | A
2 |          1 | B
3 |          1 | C
4 |          1 | D
5 |          2 | E
6 |          2 | F
7 |          3 | G
8 |          2 | H
(8 rows)
```

I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:

```id | section_id | name
----+------------+------
1 |          1 | A
2 |          1 | B
5 |          2 | E
6 |          2 | F
7 |          3 | G
(5 rows)
```

PostgreSQL v9.3 you can do a lateral join

```select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer
join lateral (
select * from t t_inner
where t_inner.section_id = t_outer.section_id
order by t_inner.name
limit 2
) t_top on true
order by t_outer.section_id;
```

Database: PostgreSQL

Ref: https://bit.ly/3AfYwZI

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