SQL Exercise: Employees location, grade, and experience over 25 years

SQL employee Database: Exercise-62 with Solution

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62. From the following table, write a SQL query to find the employees of MARKETING department come from MELBOURNE or PERTH, are in grades 3 ,4, and 5 and have at least 25 years of experience. Return department ID, employee ID, employee name, salary, department name, department location and grade.

Pictorial Presentation:

SQL exercises on employee Database: List the employees with their location and grade for MARKETING department who comes from MELBOURNE or PERTH within the grade 3 to 5 and experience over 25 years

Sample table: employees

Sample table: salary_grade

Sample table: department

Sample Solution:

SELECT e.dep_id,
FROM employees e,
     salary_grade s,
     department d
WHERE e.dep_id = d.dep_id
  AND e.salary BETWEEN s.min_sal AND s.max_sal
  AND s.grade IN (3,4,
              FROM age(CURRENT_DATE, hire_date)) > 25
  AND (d.dep_name = 'MARKETING'
       AND D.dep_location IN ('MELBOURNE',

Sample Output:

dep_id |emp_id |emp_name |salary  |dep_name  |dep_location |grade |
3001   |66928  |BLAZE    |2750.00 |MARKETING |PERTH        |4     |
3001   |64989  |ADELYN   |1700.00 |MARKETING |PERTH        |3     |
3001   |68454  |TUCKER   |1600.00 |MARKETING |PERTH        |3     |


The said query in SQL that selects the department ID, employee ID, employee name, salary, department name, department location, and salary grade of employees who work in the Marketing department located in either 'MELBOURNE' or 'PERTH', whose salary falls within the range of salary grades 3, 4, or 5, and whose hire date is more than 25 years ago from the current date.

The query joins the 'employees', 'salary_grade', and 'department' tables that returns rows that have a matching record in all three tables. The 'employees' and 'department' tables are linked based on the dep_id column.

The "WHERE" clause filters the results to employees whose department name is 'MARKETING' and department location is either 'MELBOURNE' or 'PERTH'.

By comparing the employee's salary to the "min_sal" and "max_sal" columns in the "salary_grade" table, the "BETWEEN" operator filters the results to employees whose salaries are within the salary grade range.

It further includes those employees whose hire date is more than 25 years ago from the current date using the "age" and "EXTRACT" functions. The "age" function calculates the difference between the current date and the hire date, and the "EXTRACT" function extracts the year value from the result of the "age" function.

Practice Online

Sample Database: employee

employee database structure

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Previous SQL Exercise: Employees with location, salary range, and joined in 91.
Next SQL Exercise: List the employees who are senior to their own manager.

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SQL: Tips of the Day

Grouped LIMIT in PostgreSQL: Show the first N rows for each group?

db=# SELECT * FROM xxx;
 id | section_id | name
  1 |          1 | A
  2 |          1 | B
  3 |          1 | C
  4 |          1 | D
  5 |          2 | E
  6 |          2 | F
  7 |          3 | G
  8 |          2 | H
(8 rows)

I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:

id | section_id | name
  1 |          1 | A
  2 |          1 | B
  5 |          2 | E
  6 |          2 | F
  7 |          3 | G
(5 rows)

PostgreSQL v9.3 you can do a lateral join

select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer
join lateral (
    select * from t t_inner
    where t_inner.section_id = t_outer.section_id
    order by t_inner.name
    limit 2
) t_top on true
order by t_outer.section_id;

Database: PostgreSQL

Ref: https://bit.ly/3AfYwZI


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