﻿ SQL: List the employee with their grade for the grade 4

# SQL Exercise: List the employee with their grade for the grade 4

## SQL employee Database: Exercise-64 with Solution

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64. From the following tables, write a SQL query to determine which employees have a grade of 4 and a salary between the minimum and maximum. Return all information of each employees and their grade and salary related details.

Pictorial Presentation:

Sample table: employees

Sample Solution:

``````SELECT *
FROM employees e,
WHERE e.salary BETWEEN s.min_sal AND s.max_sal
``````

Sample Output:

``` emp_id | emp_name | job_name | manager_id | hire_date  | salary  | commission | dep_id | grade | min_sal | max_sal
--------+----------+----------+------------+------------+---------+------------+--------+-------+---------+---------
66928 | BLAZE    | MANAGER  |      68319 | 1991-05-01 | 2750.00 |            |   3001 |     4 |    2101 |    3100
67832 | CLARE    | MANAGER  |      68319 | 1991-06-09 | 2550.00 |            |   1001 |     4 |    2101 |    3100
65646 | JONAS    | MANAGER  |      68319 | 1991-04-02 | 2957.00 |            |   2001 |     4 |    2101 |    3100
67858 | SCARLET  | ANALYST  |      65646 | 1997-04-19 | 3100.00 |            |   2001 |     4 |    2101 |    3100
69062 | FRANK    | ANALYST  |      65646 | 1991-12-03 | 3100.00 |            |   2001 |     4 |    2101 |    3100
(5 rows)
```

Explanation:

The said query in SQL that retrieves all the employees whose salary falls within the salary range of grade 4 and displays all columns for each matching row from two tables, 'employees' and 'salary_grade' .

The WHERE clause first checks whether the employee's salary falls within the range of minimum and maximum salaries defined for grade 4 in the "salary_grade" table.

It then retrieve data only for employees who belong to grade 4.

Relational Algebra Expression:

Relational Algebra Tree:

## Practice Online

Sample Database: employee

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Previous SQL Exercise: List the employees who are senior to their own manager.
Next SQL Exercise: List the employees in given department, joined after 91.

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## SQL: Tips of the Day

Grouped LIMIT in PostgreSQL: Show the first N rows for each group?

```db=# SELECT * FROM xxx;
id | section_id | name
----+------------+------
1 |          1 | A
2 |          1 | B
3 |          1 | C
4 |          1 | D
5 |          2 | E
6 |          2 | F
7 |          3 | G
8 |          2 | H
(8 rows)
```

I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:

```id | section_id | name
----+------------+------
1 |          1 | A
2 |          1 | B
5 |          2 | E
6 |          2 | F
7 |          3 | G
(5 rows)
```

PostgreSQL v9.3 you can do a lateral join

```select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer
join lateral (
select * from t t_inner
where t_inner.section_id = t_outer.section_id
order by t_inner.name
limit 2
) t_top on true
order by t_outer.section_id;
```

Database: PostgreSQL

Ref: https://bit.ly/3AfYwZI

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