﻿ SQL: Display the location of CLARE

# SQL Exercise: Display the location of CLARE

## SQL employee Database: Exercise-71 with Solution

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71. From the following table, write a SQL query to find the department location of employee ‘CLARE’. Return department location.

Pictorial Presentation:

Sample table: employees

Sample table: department

Sample Solution:

``````SELECT dep_location
FROM department d,
employees e
WHERE e.emp_name = 'CLARE'
AND e.dep_id = d.dep_id ;
``````

Sample Output:

``` dep_location
--------------
SYDNEY
(1 row)
```

Explanation:

The provided query in SQL that retrieves the department location of the employee named 'CLARE' by joining the 'department' and 'employees' tables based on the "dep_id" column.

The query returns a single column "dep_location" from the 'department' table where the "dep_id" column matches the "dep_id" column in the 'employees' table for the employee named 'CLARE'.

Relational Algebra Expression:

Relational Algebra Tree:

## Practice Online

Sample Database: employee

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Previous SQL Exercise: Employees who are CLERK, ANALYST in descending order.
Next SQL Exercise: Employees joining on given days, ascending in seniority.

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## SQL: Tips of the Day

Grouped LIMIT in PostgreSQL: Show the first N rows for each group?

```db=# SELECT * FROM xxx;
id | section_id | name
----+------------+------
1 |          1 | A
2 |          1 | B
3 |          1 | C
4 |          1 | D
5 |          2 | E
6 |          2 | F
7 |          3 | G
8 |          2 | H
(8 rows)
```

I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:

```id | section_id | name
----+------------+------
1 |          1 | A
2 |          1 | B
5 |          2 | E
6 |          2 | F
7 |          3 | G
(5 rows)
```

PostgreSQL v9.3 you can do a lateral join

```select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer
join lateral (
select * from t t_inner
where t_inner.section_id = t_outer.section_id
order by t_inner.name
limit 2
) t_top on true
order by t_outer.section_id;
```

Database: PostgreSQL

Ref: https://bit.ly/3AfYwZI

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