SQL Exercise: Display the location of CLARE
SQL employee Database: Exercise-71 with Solution
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71. From the following table, write a SQL query to find the department location of employee ‘CLARE’. Return department location.
Pictorial Presentation:

Sample table: employees
Sample table: department
Sample Solution:
SELECT dep_location
FROM department d,
employees e
WHERE e.emp_name = 'CLARE'
AND e.dep_id = d.dep_id ;
Sample Output:
dep_location -------------- SYDNEY (1 row)
Explanation:
The provided query in SQL that retrieves the department location of the employee named 'CLARE' by joining the 'department' and 'employees' tables based on the "dep_id" column.
The query returns a single column "dep_location" from the 'department' table where the "dep_id" column matches the "dep_id" column in the 'employees' table for the employee named 'CLARE'.
Relational Algebra Expression:

Relational Algebra Tree:

Practice Online
Sample Database: employee

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Previous SQL Exercise: Employees who are CLERK, ANALYST in descending order.
Next SQL Exercise: Employees joining on given days, ascending in seniority.
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SQL: Tips of the Day
Grouped LIMIT in PostgreSQL: Show the first N rows for each group?
db=# SELECT * FROM xxx; id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 3 | 1 | C 4 | 1 | D 5 | 2 | E 6 | 2 | F 7 | 3 | G 8 | 2 | H (8 rows)
I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 5 | 2 | E 6 | 2 | F 7 | 3 | G (5 rows)
PostgreSQL v9.3 you can do a lateral join
select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer join lateral ( select * from t t_inner where t_inner.section_id = t_outer.section_id order by t_inner.name limit 2 ) t_top on true order by t_outer.section_id;
Database: PostgreSQL
Ref: https://bit.ly/3AfYwZI
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