SQL Exercise: List the employees along with grades in ascending order
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83. From the following tables, write a SQL query to find the employees along with grades in ascending order. Return complete information about the employees.
Sample table: employees
+-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+ | EMPLOYEE_ID | FIRST_NAME | LAST_NAME | EMAIL | PHONE_NUMBER | HIRE_DATE | JOB_ID | SALARY | COMMISSION_PCT | MANAGER_ID | DEPARTMENT_ID | +-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+ | 100 | Steven | King | SKING | 515.123.4567 | 2003-06-17 | AD_PRES | 24000.00 | 0.00 | 0 | 90 | | 101 | Neena | Kochhar | NKOCHHAR | 515.123.4568 | 2005-09-21 | AD_VP | 17000.00 | 0.00 | 100 | 90 | | 102 | Lex | De Haan | LDEHAAN | 515.123.4569 | 2001-01-13 | AD_VP | 17000.00 | 0.00 | 100 | 90 | | 103 | Alexander | Hunold | AHUNOLD | 590.423.4567 | 2006-01-03 | IT_PROG | 9000.00 | 0.00 | 102 | 60 | | 104 | Bruce | Ernst | BERNST | 590.423.4568 | 2007-05-21 | IT_PROG | 6000.00 | 0.00 | 103 | 60 | | 105 | David | Austin | DAUSTIN | 590.423.4569 | 2005-06-25 | IT_PROG | 4800.00 | 0.00 | 103 | 60 | | 106 | Valli | Pataballa | VPATABAL | 590.423.4560 | 2006-02-05 | IT_PROG | 4800.00 | 0.00 | 103 | 60 | | 107 | Diana | Lorentz | DLORENTZ | 590.423.5567 | 2007-02-07 | IT_PROG | 4200.00 | 0.00 | 103 | 60 | | 108 | Nancy | Greenberg | NGREENBE | 515.124.4569 | 2002-08-17 | FI_MGR | 12008.00 | 0.00 | 101 | 100 | | 109 | Daniel | Faviet | DFAVIET | 515.124.4169 | 2002-08-16 | FI_ACCOUNT | 9000.00 | 0.00 | 108 | 100 | ......... | 206 | William | Gietz | WGIETZ | 515.123.8181 | 2002-06-07 | AC_ACCOUNT | 8300.00 | 0.00 | 205 | 110 | +-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+
Sample table: salary_grade
grade | min_sal | max_sal
-------+---------+---------
1 | 800 | 1300
2 | 1301 | 1500
3 | 1501 | 2100
4 | 2101 | 3100
5 | 3101 | 9999
Pictorial Presentation:
Sample table: employees
Sample table: salary_grade
Sample Solution:
SELECT *
FROM employees e,
salary_grade s
WHERE e.salary BETWEEN s.min_sal AND s.max_sal
ORDER BY grade ASC;
OR
SELECT *
FROM employees e,
salary_grade s
WHERE e.salary >= s.min_sal
AND e.salary <= s.max_sal
ORDER BY s.grade ASC;
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id | grade | min_sal | max_sal --------+----------+-----------+------------+------------+---------+------------+--------+-------+---------+--------- 63679 | SANDRINE | CLERK | 69062 | 1990-12-18 | 900.00 | | 2001 | 1 | 800 | 1300 68736 | ADNRES | CLERK | 67858 | 1997-05-23 | 1200.00 | | 2001 | 1 | 800 | 1300 69000 | JULIUS | CLERK | 66928 | 1991-12-03 | 1050.00 | | 3001 | 1 | 800 | 1300 65271 | WADE | SALESMAN | 66928 | 1991-02-22 | 1350.00 | 600.00 | 3001 | 2 | 1301 | 1500 66564 | MADDEN | SALESMAN | 66928 | 1991-09-28 | 1350.00 | 1500.00 | 3001 | 2 | 1301 | 1500 69324 | MARKER | CLERK | 67832 | 1992-01-23 | 1400.00 | | 1001 | 2 | 1301 | 1500 64989 | ADELYN | SALESMAN | 66928 | 1991-02-20 | 1700.00 | 400.00 | 3001 | 3 | 1501 | 2100 68454 | TUCKER | SALESMAN | 66928 | 1991-09-08 | 1600.00 | 0.00 | 3001 | 3 | 1501 | 2100 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 | 4 | 2101 | 3100 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 | 4 | 2101 | 3100 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 | 4 | 2101 | 3100 67858 | SCARLET | ANALYST | 65646 | 1997-04-19 | 3100.00 | | 2001 | 4 | 2101 | 3100 69062 | FRANK | ANALYST | 65646 | 1991-12-03 | 3100.00 | | 2001 | 4 | 2101 | 3100 68319 | KAYLING | PRESIDENT | | 1991-11-18 | 6000.00 | | 1001 | 5 | 3101 | 9999 (14 rows)
Explanation:
The said query in SQL that selects all columns from the tables 'employees' and 'salary_grade' where the employee's salary falls within the minimum and maximum salary range of a certain grade. The results are ordered by grade in ascending order.
The implicit join between 'employees' and 'salary_grade' table where the employee's salary must be between the minimum and maximum salary of the grade.
Relational Algebra Expression:
Relational Algebra Tree:
Relational Algebra Expression:
Relational Algebra Tree:
Go to:
PREV : Employees under a given department ORDER BY dep_id ASC.
NEXT : Employees according to the department in ASC order.
Practice Online
Sample Database: employees
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