﻿ SQL: List employees along with details of their departments

# SQL Exercise: List employees along with details of their departments

## SQL employee Database: Exercise-87 with Solution

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87. From the following table, write a SQL query to list the details of the employees along with the details of their departments.

Sample table: employees

Sample table: department

Sample Solution:

``````SELECT *
FROM employees e,
department d
WHERE e.dep_id= d.dep_id;
``````

Sample Output:

``` emp_id | emp_name | job_name  | manager_id | hire_date  | salary  | commission | dep_id | dep_id | dep_name  | dep_location
--------+----------+-----------+------------+------------+---------+------------+--------+--------+-----------+--------------
68319 | KAYLING  | PRESIDENT |            | 1991-11-18 | 6000.00 |            |   1001 |   1001 | FINANCE   | SYDNEY
66928 | BLAZE    | MANAGER   |      68319 | 1991-05-01 | 2750.00 |            |   3001 |   3001 | MARKETING | PERTH
67832 | CLARE    | MANAGER   |      68319 | 1991-06-09 | 2550.00 |            |   1001 |   1001 | FINANCE   | SYDNEY
65646 | JONAS    | MANAGER   |      68319 | 1991-04-02 | 2957.00 |            |   2001 |   2001 | AUDIT     | MELBOURNE
67858 | SCARLET  | ANALYST   |      65646 | 1997-04-19 | 3100.00 |            |   2001 |   2001 | AUDIT     | MELBOURNE
69062 | FRANK    | ANALYST   |      65646 | 1991-12-03 | 3100.00 |            |   2001 |   2001 | AUDIT     | MELBOURNE
63679 | SANDRINE | CLERK     |      69062 | 1990-12-18 |  900.00 |            |   2001 |   2001 | AUDIT     | MELBOURNE
64989 | ADELYN   | SALESMAN  |      66928 | 1991-02-20 | 1700.00 |     400.00 |   3001 |   3001 | MARKETING | PERTH
65271 | WADE     | SALESMAN  |      66928 | 1991-02-22 | 1350.00 |     600.00 |   3001 |   3001 | MARKETING | PERTH
66564 | MADDEN   | SALESMAN  |      66928 | 1991-09-28 | 1350.00 |    1500.00 |   3001 |   3001 | MARKETING | PERTH
68454 | TUCKER   | SALESMAN  |      66928 | 1991-09-08 | 1600.00 |       0.00 |   3001 |   3001 | MARKETING | PERTH
68736 | ADNRES   | CLERK     |      67858 | 1997-05-23 | 1200.00 |            |   2001 |   2001 | AUDIT     | MELBOURNE
69000 | JULIUS   | CLERK     |      66928 | 1991-12-03 | 1050.00 |            |   3001 |   3001 | MARKETING | PERTH
69324 | MARKER   | CLERK     |      67832 | 1992-01-23 | 1400.00 |            |   1001 |   1001 | FINANCE   | SYDNEY
(14 rows)
```

Explanation:

The given query in SQL that selects all columns from the tables 'employees' and 'department' using a join. The query returns all rows where the dep_id column in the employees table matches the dep_id column in the department table.

This could be define as an inner join, which returns only the rows where there is a match in both tables based on the specified condition.

## Practice Online

Sample Database: employee

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Previous SQL Exercise: List employees working for department 1001 or 2001.
Next SQL Exercise: List the employees who are senior to their own MANAGERS.

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