SQL Exercise: Managers salary exceeds the average of their employees

SQL subqueries on employee Database: Exercise-35 with Solution

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35. From the following table, write a SQL query to find those managers whose salary is more than the average salary of his employees. Return complete information about the employees.

Sample table: employees

Sample Solution:

SELECT *
FROM employees m
WHERE m.emp_id IN
    (SELECT manager_id
     FROM employees)
  AND m.salary >
    (SELECT avg(e.salary)
     FROM employees e
     WHERE e.manager_id = m.emp_id );

Sample Output:

 emp_id | emp_name | job_name  | manager_id | hire_date  | salary  | commission | dep_id
--------+----------+-----------+------------+------------+---------+------------+--------
  67832 | CLARE    | MANAGER   |      68319 | 1991-06-09 | 2550.00 |            |   1001
  69062 | FRANK    | ANALYST   |      65646 | 1991-12-03 | 3100.00 |            |   2001
  68319 | KAYLING  | PRESIDENT |            | 1991-11-18 | 6000.00 |            |   1001
  67858 | SCARLET  | ANALYST   |      65646 | 1997-04-19 | 3100.00 |            |   2001
  66928 | BLAZE    | MANAGER   |      68319 | 1991-05-01 | 2750.00 |            |   3001
(5 rows)

Explanation:

The given query in SQL that retrieves all columns from the employees table for all employees who are also managers and whose salary is greater than the average salary of the employees they manage.

The WHERE clause includes the emp_id in the list who are also managers obtained from a subquery.

The subquery that selects the manager id from the employees table.

The query then filters the rows to only those where the salary of the manager is greater than the average salary of the employees they manage obtained from another subquery.

The subquery calculates the average salary of employees managed by each manager.

Practice Online

Structure of employee Database:

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