﻿ SQL: Total remuneration of all sales person of a department

# SQL Exercise: Total remuneration of all sales person of a department

## SQL subqueries on employee Database: Exercise-69 with Solution

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69. From the following tables, write a SQL query to find compute the total remuneration (salary + commission) of all sales person of MARKETING department. Return complete information about the employees.

Sample table: employees

Sample table: department

Sample Solution:

``````SELECT *
FROM employees e
WHERE salary+commission IN
(SELECT salary+commission
FROM employees e,
department d
WHERE e.dep_id=d.dep_id
AND d.dep_name = 'MARKETING'
AND e.job_name = 'SALESMAN');
``````

Sample Output:

``` emp_id | emp_name | job_name | manager_id | hire_date  | salary  | commission | dep_id
--------+----------+----------+------------+------------+---------+------------+--------
64989 | ADELYN   | SALESMAN |      66928 | 1991-02-20 | 1700.00 |     400.00 |   3001
65271 | WADE     | SALESMAN |      66928 | 1991-02-22 | 1350.00 |     600.00 |   3001
66564 | MADDEN   | SALESMAN |      66928 | 1991-09-28 | 1350.00 |    1500.00 |   3001
68454 | TUCKER   | SALESMAN |      66928 | 1991-09-08 | 1600.00 |       0.00 |   3001
(4 rows)
```

Explanation:

The said query in SQL that retrieves all the records from the 'employees' table where the sum of the salary and commission is present in the subquery that selects the sum of the salary and commission for all employees in the Marketing department with the job_name 'SALESMAN'.

The subquery includes a join with the department table to filter only employees in the Marketing department.

## Practice Online

Structure of employee Database:

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