SQL Exercise: Names of patients, their doctors, and medications
SQL hospital Database: Exercise-19 with Solution
19. From the following tables, write a SQL query to locate the patients' treating physicians and medications. Return Patient name as "Patient", Physician name as "Physician", Medication name as "Medication".
Sample table: patient
Sample table: prescribes
Sample table: physician
Sample table: medication
Sample Solution:
SELECT t.name AS "Patient",
p.name AS "Physician",
m.name AS "Medication"
FROM patient t
JOIN prescribes s ON s.patient=t.ssn
JOIN physician p ON s.physician=p.employeeid
JOIN medication m ON s.medication=m.code;
Sample Output:
Patient | Physician | Medication ------------+-------------+-------------- John Smith | John Dorian | Procrastin-X Dennis Doe | Molly Clock | Thesisin Dennis Doe | Molly Clock | Thesisin (3 rows)
Explanation:
The said query in SQL that returns information about medications prescribed to patients by their physicians, including the patient's name, the physician's name, and the medication name.
The query performs a join between the 'patient', 'prescribes', 'physician', and 'medication' tables, based on their relational columns.
The 'prescribes' and 'patient' tables are joins based on the patient and ssn columns, the 'prescribes' and 'physician tables are joins based on the physician and employeeid columns, and the 'medication ' and the 'prescribes' and 'medication' tables are joins based on the medication and code columns.
Practice Online
E R Diagram of Hospital Database:

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Previous SQL Exercise: Patients and their physicians who do not need a nurse.
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SQL: Tips of the Day
Grouped LIMIT in PostgreSQL: Show the first N rows for each group?
db=# SELECT * FROM xxx; id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 3 | 1 | C 4 | 1 | D 5 | 2 | E 6 | 2 | F 7 | 3 | G 8 | 2 | H (8 rows)
I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 5 | 2 | E 6 | 2 | F 7 | 3 | G (5 rows)
PostgreSQL v9.3 you can do a lateral join
select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer join lateral ( select * from t t_inner where t_inner.section_id = t_outer.section_id order by t_inner.name limit 2 ) t_top on true order by t_outer.section_id;
Database: PostgreSQL
Ref: https://bit.ly/3AfYwZI
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