﻿ SQL: Find the floor and block with a given room number

# SQL Exercise: Find the floor and block with a given room number

## SQL hospital Database: Exercise-5 with Solution

5. From the following table, write a SQL query to locate the floor and block where room number 212 is located. Return block floor as "Floor" and block code as "Block".

Sample table: room

Sample Solution:

``````SELECT blockfloor AS "Floor",
blockcode AS "Block"
FROM room
WHERE roomnumber=212;
``````

Sample Output:

``` Floor | Block
-------+-------
2 |     2
(1 row)
```

Explanation:

The said query in SQL that selects the "blockfloor" and "blockcode" columns from the 'room' table where the "roomnumber" is equal to 212.

The "blockfloor" column aliased as "Floor" and the "blockcode" column aliased as "Block".

Pictorial presentation:

## Practice Online

E R Diagram of Hospital Database:

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Previous SQL Exercise: Patients with at least one physician appointment.
Next SQL Exercise: Count the number available rooms.

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## SQL: Tips of the Day

Grouped LIMIT in PostgreSQL: Show the first N rows for each group?

```db=# SELECT * FROM xxx;
id | section_id | name
----+------------+------
1 |          1 | A
2 |          1 | B
3 |          1 | C
4 |          1 | D
5 |          2 | E
6 |          2 | F
7 |          3 | G
8 |          2 | H
(8 rows)
```

I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:

```id | section_id | name
----+------------+------
1 |          1 | A
2 |          1 | B
5 |          2 | E
6 |          2 | F
7 |          3 | G
(5 rows)
```

PostgreSQL v9.3 you can do a lateral join

```select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer
join lateral (
select * from t t_inner
where t_inner.section_id = t_outer.section_id
order by t_inner.name
limit 2
) t_top on true
order by t_outer.section_id;
```

Database: PostgreSQL

Ref: https://bit.ly/3AfYwZI

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