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SQL Exercises: Count all orders for a specific date

SQL Aggregate Functions: Exercise-18 with Solution

From the following table, write a SQL query to count all the orders generated on '2012-08-17'. Return number of orders.

Sample table: orders


Sample Solution:

SELECT COUNT(*) 
FROM orders 
WHERE ord_date='2012-08-17';

Output of the Query:

count
2

Code Explanation:

The said SQL query retrieves the count of rows from the 'orders' table where the ord_date is equal to '2012-08-17'. The result will be a single row with a single column indicating the number of orders placed on '2012-08-17'.

Relational Algebra Expression:

Relational Algebra Expression: Count all orders of a specific date.

Relational Algebra Tree:

Relational Algebra Tree: Count all orders of a specific date.

Explanation:

Syntax of count all order in a specified date

Visual presentation:

Count all order in a specified date

Practice Online


Query Visualization:

Duration:

Query visualization of Count all orders of a specific date - Duration

Rows:

Query visualization of Count all orders of a specific date - Rows

Cost:

Query visualization of Count all orders of a specific date - Cost

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Previous SQL Exercise: Customer with the highest purchase amount.
Next SQL Exercise: Number of non NULL city values for salesmen.

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