﻿ SQL: Display customer name, city, grade

# SQL Exercise: Display customer name, city, grade

## SQL Formatting Output: Exercise-6 with Solution

From the following table, write a SQL query to find all the customers. Sort the result-set by customer_id. Return cust_name, city, grade.

Sample table: customer

``` customer_id |   cust_name    |    city    | grade | salesman_id
-------------+----------------+------------+-------+-------------
3002 | Nick Rimando   | New York   |   100 |        5001
3007 | Brad Davis     | New York   |   200 |        5001
3005 | Graham Zusi    | California |   200 |        5002
3008 | Julian Green   | London     |   300 |        5002
3004 | Fabian Johnson | Paris      |   300 |        5006
3009 | Geoff Cameron  | Berlin     |   100 |        5003
3003 | Jozy Altidor   | Moscow     |   200 |        5007
3001 | Brad Guzan     | London     |       |        5005
```

Sample Solution:

``````-- This query selects specific columns ('cust_name', 'city', 'grade') from the 'customer' table and orders the result set by 'customer_id' in ascending order.
-- Specifies the table from which to retrieve the data (in this case, 'customer').
FROM customer
-- Orders the result set by the 'customer_id' column in ascending order.
ORDER BY customer_id;
``````

Output of the Query:

```cust_name	city		grade
Nick Rimando	New York	100
Jozy Altidor	Moscow		200
Fabian Johnson	Paris		300
Graham Zusi	California	200
Julian Green	London		300
Geoff Cameron	Berlin		100```

Code Explanation:

The said query in SQL retrieves data from the 'customer' table and returns the columns cust_name, city, and grade.
The "ORDER BY customer_id" clause sorts the rows in the result set based on the values in the customer_id column.

Relational Algebra Expression:

Relational Algebra Tree:

Explanation :

Visual presentation :

## Query Visualization:

Duration:

Rows:

Cost:

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Previous SQL Exercise: Oldest orders first on the highest purchase amount.
Next SQL Exercise: Salesman details by smallest ID along with order date.

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