SQL Exercises: Make a report with customer name, city, order number, date, and amount in ascending order on order date to find either any of the existing customer have placed no order or placed one or more orders
SQL JOINS: Exercise-10 with Solution
Write a SQL statement to make a report with customer name, city, order number, order date, and order amount in ascending order according to the order date to find that either any of the existing customers have placed no order or placed one or more orders.
Sample table: orders
Sample table: customer
SELECT a.cust_name,a.city, b.ord_no, b.ord_date,b.purch_amt AS "Order Amount" FROM customer a LEFT OUTER JOIN orders b ON a.customer_id=b.customer_id order by b.ord_date;
Output of the Query:
cust_name city ord_no ord_date Order Amount Nick Rimando New York 70013 2012-04-25 3045.60 Julian Green London 70012 2012-06-27 250.45 Brad Davis New York 70005 2012-07-27 2400.60 Jozy Altidor Moscow 70011 2012-08-17 75.29 Geoff Cameron Berlin 70004 2012-08-17 110.50 Brad Guzan London 70009 2012-09-10 270.65 Nick Rimando New York 70008 2012-09-10 5760.00 Graham Zusi California 70007 2012-09-10 948.50 Graham Zusi California 70001 2012-10-05 150.50 Nick Rimando New York 70002 2012-10-05 65.26 Fabian Johnson Paris 70010 2012-10-10 1983.43 Geoff Cameron Berlin 70003 2012-10-10 2480.40
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Previous: Write a SQL statement to make a list in ascending order for the customer who holds a grade less than 300 and works either through a salesman or by own.
Next: Write a SQL statement to make a report with customer name, city, order number, order date, order amount salesman name and commission to find that either any of the existing customers have placed no order or placed one or more orders by their salesman or by own.
What is the difficulty level of this exercise?