SQL Exercise: A salesperson who gets a commission of at least 12%

Last update on April 22 2025 10:56:14 (UTC/GMT +8 hours)

4. High Commission Salespeople

From the following tables write a SQL query to find salespeople who received commissions of more than 12 percent from the company. Return Customer Name, customer city, Salesman, commission.

Sample table: customer

 customer_id |   cust_name    |    city    | grade | salesman_id 
-------------+----------------+------------+-------+-------------
        3002 | Nick Rimando   | New York   |   100 |        5001
        3007 | Brad Davis     | New York   |   200 |        5001
        3005 | Graham Zusi    | California |   200 |        5002
        3008 | Julian Green   | London     |   300 |        5002
        3004 | Fabian Johnson | Paris      |   300 |        5006
        3009 | Geoff Cameron  | Berlin     |   100 |        5003
        3003 | Jozy Altidor   | Moscow     |   200 |        5007
        3001 | Brad Guzan     | London     |       |        5005

Sample table: salesman

 salesman_id |    name    |   city   | commission 
-------------+------------+----------+------------
        5001 | James Hoog | New York |       0.15
        5002 | Nail Knite | Paris    |       0.13
        5005 | Pit Alex   | London   |       0.11
        5006 | Mc Lyon    | Paris    |       0.14
        5007 | Paul Adam  | Rome     |       0.13
        5003 | Lauson Hen | San Jose |       0.12

Sample Solution:

-- Selecting specific columns and renaming them for clarity
SELECT a.cust_name AS "Customer Name", 
       a.city, 
       b.name AS "Salesman", 
       b.commission 
-- Specifying the tables to retrieve data from ('customer' as 'a' and 'salesman' as 'b')
FROM customer a 
-- Performing an inner join based on the salesman_id
INNER JOIN salesman b 
ON a.salesman_id = b.salesman_id 
-- Filtering the results based on a condition (commission greater than 0.12)
WHERE b.commission > 0.12;

Output of the Query:

Customer Name	city		Salesman	commission
Nick Rimando	New York	James Hoog	0.15
Brad Davis	New York	James Hoog	0.15
Graham Zusi	California	Nail Knite	0.13
Julian Green	London		Nail Knite	0.13
Fabian Johnson	Paris		Mc Lyon		0.14
Jozy Altidor	Moscow		Paul Adam	0.13

Explanation:

The said SQL query that is used to select specific columns from two tables, customer and salesman, and join them using the 'salesman_id' column.
The query selects the 'cust_name' column from the customer table as 'Customer Name', the 'city' column from the customer table, the 'name' column from the salesman table as 'Salesman', and the 'commission' column from the salesman table.
The query uses an inner join, which only returns rows where there is a match in both tables on the specified join column. Additionally, it has a WHERE clause that filters out the rows where the commission of the Salesman is less than or equal to 0.12. So, only the rows where commission of the Salesman is greater than 0.12 will be returned.

Visual Explanation:

Practice Online

Query Visualization:

Duration:

Rows:

Cost:

For more Practice: Solve these Related Problems:

• Write a SQL query to retrieve customer name, customer city, salesperson name, and commission for records where the salesperson’s commission exceeds 12%.
• Write a SQL query to list customer and salesperson details, filtering the output to only include salespeople with commissions greater than 12% and customers from cities starting with 'N'.
• Write a SQL query to display details of customers and their salespeople, where only records with commission over 12% are included and the customer grade is not null.
• Write a SQL query to fetch customer and salesperson data with commission above 12%, sorting the results by salesperson name.

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