SQL Exercise: Display commission of the salesman for an order
SQL JOINS: Exercise-6 with Solution
From the following tables write a SQL query to find the details of an order. Return ord_no, ord_date, purch_amt, Customer Name, grade, Salesman, commission.
Sample table: orders
Sample table: customer
Sample table: salesman
Sample Solution:
SELECT a.ord_no,a.ord_date,a.purch_amt,
b.cust_name AS "Customer Name", b.grade,
c.name AS "Salesman", c.commission
FROM orders a
INNER JOIN customer b
ON a.customer_id=b.customer_id
INNER JOIN salesman c
ON a.salesman_id=c.salesman_id;
Output of the Query:
ord_no ord_date purch_amt Customer Name grade Salesman commission 70009 2012-09-10 270.65 Brad Guzan Pit Alex 0.11 70002 2012-10-05 65.26 Nick Rimando 100 James Hoog 0.15 70004 2012-08-17 110.50 Geoff Cameron 100 Lauson Hen 0.12 70005 2012-07-27 2400.60 Brad Davis 200 James Hoog 0.15 70008 2012-09-10 5760.00 Nick Rimando 100 James Hoog 0.15 70010 2012-10-10 1983.43 Fabian Johnson 300 Mc Lyon 0.14 70003 2012-10-10 2480.40 Geoff Cameron 100 Lauson Hen 0.12 70011 2012-08-17 75.29 Jozy Altidor 200 Paul Adam 0.13 70013 2012-04-25 3045.60 Nick Rimando 100 James Hoog 0.15 70001 2012-10-05 150.50 Graham Zusi 200 Nail Knite 0.13 70007 2012-09-10 948.50 Graham Zusi 200 Nail Knite 0.13 70012 2012-06-27 250.45 Julian Green 300 Nail Knite 0.13
Explanation:
The said SQL query that uses the INNER JOIN clause to combine rows from three tables: orders, customer, and salesman.
The query retrieves the ord_no, ord_date, purch_amt, cust_name, grade, name, and commission from the three tables where the customer_id from the orders table matches the customer_id from the customer table, and the salesman_id from the orders table matches the salesman_id from the salesman table.
The query also uses the AS keyword to rename the cust_name and name columns as 'Customer Name' and 'Salesman' respectively.
Visual Explanation:
Practice Online
Query Visualization:
Duration:
Rows:
Cost:
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Previous SQL Exercise: Customers and salespeople live in different cities.
Next SQL Exercise: Join within the tables salesman, customer and orders.
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SQL: Tips of the Day
Grouped LIMIT in PostgreSQL: Show the first N rows for each group?
db=# SELECT * FROM xxx; id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 3 | 1 | C 4 | 1 | D 5 | 2 | E 6 | 2 | F 7 | 3 | G 8 | 2 | H (8 rows)
I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 5 | 2 | E 6 | 2 | F 7 | 3 | G (5 rows)
PostgreSQL v9.3 you can do a lateral join
select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer
join lateral (
select * from t t_inner
where t_inner.section_id = t_outer.section_id
order by t_inner.name
limit 2
) t_top on true
order by t_outer.section_id;
Database: PostgreSQL
Ref: https://bit.ly/3AfYwZI
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