SQL Exercises: Customer and salesmen who lives in the same city
SQL Query on Multiple Tables: Exercise-1 with Solution
From the following tables, write a SQL query to find the salespeople and customers who live in the same city. Return customer name, salesperson name and salesperson city.
Sample table: salesman
Sample table: customer
Sample Solution:
SELECT customer.cust_name,
salesman.name, salesman.city
FROM salesman, customer
WHERE salesman.city = customer.city;
Output of the query:
cust_name name city Nick Rimando James Hoog New York Brad Davis James Hoog New York Julian Green Pit Alex London Fabian Johnson Mc Lyon Paris Fabian Johnson Nail Knite Paris Brad Guzan Pit Alex London
Code Explanation:
The said query in SQL that joins the 'salesman' and 'customer' tables based on the city column. The result set includes the customer name (cust_name), salesman name (name), and city from the salesman table. The WHERE clause specifies the join condition between the two tables, which is that the city column must be equal in both tables.
Relational Algebra Expression:

Relational Algebra Tree:

Explanation:

Visual presentation:

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SQL: Tips of the Day
Grouped LIMIT in PostgreSQL: Show the first N rows for each group?
db=# SELECT * FROM xxx; id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 3 | 1 | C 4 | 1 | D 5 | 2 | E 6 | 2 | F 7 | 3 | G 8 | 2 | H (8 rows)
I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 5 | 2 | E 6 | 2 | F 7 | 3 | G (5 rows)
PostgreSQL v9.3 you can do a lateral join
select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer join lateral ( select * from t t_inner where t_inner.section_id = t_outer.section_id order by t_inner.name limit 2 ) t_top on true order by t_outer.section_id;
Database: PostgreSQL
Ref: https://bit.ly/3AfYwZI
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