SQL Exercises: Employees whose salary is higher than title is PU_MAN

Last update on March 12 2025 12:12:02 (UTC/GMT +8 hours)

From the following table, write a SQL query to find those employees whose salary exceeds the salary of all those employees whose job title is "PU_MAN". Exclude job title ‘PU_MAN’. Return employee ID, first name, last name, job ID.

Sample table: employees

+-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+
| EMPLOYEE_ID | FIRST_NAME  | LAST_NAME   | EMAIL    | PHONE_NUMBER       | HIRE_DATE  | JOB_ID     | SALARY   | COMMISSION_PCT | MANAGER_ID | DEPARTMENT_ID |
+-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+
|         100 | Steven      | King        | SKING    | 515.123.4567       | 2003-06-17 | AD_PRES    | 24000.00 |           0.00 |          0 |            90 |
|         101 | Neena       | Kochhar     | NKOCHHAR | 515.123.4568       | 2005-09-21 | AD_VP      | 17000.00 |           0.00 |        100 |            90 |
|         102 | Lex         | De Haan     | LDEHAAN  | 515.123.4569       | 2001-01-13 | AD_VP      | 17000.00 |           0.00 |        100 |            90 |
|         103 | Alexander   | Hunold      | AHUNOLD  | 590.423.4567       | 2006-01-03 | IT_PROG    |  9000.00 |           0.00 |        102 |            60 |
|         104 | Bruce       | Ernst       | BERNST   | 590.423.4568       | 2007-05-21 | IT_PROG    |  6000.00 |           0.00 |        103 |            60 |
|         105 | David       | Austin      | DAUSTIN  | 590.423.4569       | 2005-06-25 | IT_PROG    |  4800.00 |           0.00 |        103 |            60 |
|         106 | Valli       | Pataballa   | VPATABAL | 590.423.4560       | 2006-02-05 | IT_PROG    |  4800.00 |           0.00 |        103 |            60 |
|         107 | Diana       | Lorentz     | DLORENTZ | 590.423.5567       | 2007-02-07 | IT_PROG    |  4200.00 |           0.00 |        103 |            60 |
|         108 | Nancy       | Greenberg   | NGREENBE | 515.124.4569       | 2002-08-17 | FI_MGR     | 12008.00 |           0.00 |        101 |           100 |
|         109 | Daniel      | Faviet      | DFAVIET  | 515.124.4169       | 2002-08-16 | FI_ACCOUNT |  9000.00 |           0.00 |        108 |           100 |
|         110 | John        | Chen        | JCHEN    | 515.124.4269       | 2005-09-28 | FI_ACCOUNT |  8200.00 |           0.00 |        108 |           100 |
....................
+-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+

View the table

Sample Solution:

-- Selecting specific columns (employee_id, first_name, last_name, job_id) from the 'employees' table
SELECT employee_id, first_name, last_name, job_id  

-- Filtering rows based on the condition that the 'salary' is greater than all salaries in the result set of a subquery
FROM employees  

-- Subquery to find salaries where the 'job_id' is 'PU_MAN' in the 'employees' table
WHERE salary > ALL  

  (SELECT salary  
   FROM employees  

   -- Subquery to select salaries where the 'job_id' is 'PU_MAN'
   WHERE job_id = 'PU_MAN'
  )  

-- Additional condition to exclude rows where the 'job_id' is 'PU_MAN' from the result set
AND job_id <> 'PU_MAN';

Sample Output:

employee_id	first_name	last_name	job_id
100		Steven		King		AD_PRES
101		Neena		Kochhar		AD_VP
102		Lex		De Haan		AD_VP
108		Nancy		Greenberg	FI_MGR
145		John		Russell		SA_MAN
146		Karen		Partners	SA_MAN
147		Alberto		Errazuriz	SA_MAN
168		Lisa		Ozer		SA_REP
201		Michael		Hartstein	MK_MAN
205		Shelley		Higgins		AC_MGR

Code Explanation:

The said query in SQL that retrieves the employee ID, first name, last name, and job ID of all employees who have a salary higher than all employees with the job ID "PU_MAN", and do not have the job ID "PU_MAN" themselves. A subuery in the "WHERE" clause is used to retrieve the salaries of all employees who have the job ID "PUq_MAN" assigned to their job title. Using the keyword "ALL" in the outer query, the salary of each employee is then compared with the result of the subquery. The additional condition "AND job_id <> 'PU_MAN'", excludes employees with the job ID "PU_MAN" from the result set.

Visual Presentation:

Alternative Statements:

Using JOIN:

SELECT e1.employee_id, e1.first_name, e1.last_name, e1.job_id 
FROM employees e1
JOIN employees e2 ON e1.salary > e2.salary
WHERE e2.job_id = 'PU_MAN' AND e1.job_id <> 'PU_MAN';

Using EXISTS:

SELECT employee_id, first_name, last_name, job_id 
FROM employees e1
WHERE EXISTS (
    SELECT 1
    FROM employees e2
    WHERE e1.salary > e2.salary
    AND e2.job_id = 'PU_MAN'
    AND e1.job_id <> 'PU_MAN'
);

Practice Online

Query Visualization:

Duration:

Rows:

Cost:

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