﻿ SQL - Salary exceeds 50% of their departments total salary

SQL Exercises: Salary exceeds 50% of their departments total salary

SQL SUBQUERY: Exercise-31 with Solution

From the following tables, write a SQL query to find those employees whose salaries exceed 50% of their department's total salary bill. Return first name, last name.

Sample table: employees

Sample Solution:

SELECT e1.first_name, e1.last_name
FROM employees e1
WHERE salary >
( SELECT (SUM(salary))*.5
FROM employees e2
WHERE e1.department_id=e2.department_id);

Sample Output:

first_name	last_name
Kimberely	Grant
Jennifer	Whalen
Michael		Hartstein
Susan		Mavris
Hermann		Baer
Shelley		Higgins

Code Explanation:

The said query in SQL that retrieves the first name and last name of employees whose salary is greater than 50% of the total sum of salaries in their department.
The WHERE clause specifies the condition that filters the rows returned by the query. In this case, the salary of the employee must be greater than 50% of the sum of all salaries in the same department.

Visual Presentation:

Alternative Statements:

Using Subquery with IN:

SELECT e1.first_name, e1.last_name
FROM employees e1
WHERE salary > 0.5 * (
SELECT SUM(salary)
FROM employees e2
WHERE e1.department_id = e2.department_id
GROUP BY department_id
);

Using Subquery with JOIN:

SELECT e1.first_name, e1.last_name
FROM employees e1
JOIN (
SELECT department_id, SUM(salary) as total_salary
FROM employees
GROUP BY department_id
) e2
ON e1.department_id = e2.department_id
WHERE e1.salary > e2.total_salary * 0.5;

Query Visualization:

Duration:

Rows:

Cost:

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Previous SQL Exercise: Manager who works for a department based in the US.
Next SQL Exercise: Find out the details of employees who are managers.

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SQL: Tips of the Day

How to combine date from one field with time from another field - MS SQL Server

You can simply add the two.

• if the Time part of your Date column is always zero
• and the Date part of your Time column is also always zero (base date: January 1, 1900)

Adding them returns the correct result-

SELECT Combined = MyDate + MyTime FROM MyTable

Ref: https://bit.ly/3wldJYf

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