SQL Exercises: Customers who ordered on August 17, 2012

SQL SUBQUERY: Exercise-10 with Solution

10. From the following tables write SQL query to find the customers who placed orders on 17th August 2012. Return ord_no, purch_amt, ord_date, customer_id, salesman_id and cust_name.

ord_no      purch_amt   ord_date    customer_id  salesman_id
----------  ----------  ----------  -----------  -----------
70001       150.5       2012-10-05  3005         5002
70009       270.65      2012-09-10  3001         5005
70002       65.26       2012-10-05  3002         5001
70004       110.5       2012-08-17  3009         5003
70007       948.5       2012-09-10  3005         5002
70005       2400.6      2012-07-27  3007         5001
70008       5760        2012-09-10  3002         5001
70010       1983.43     2012-10-10  3004         5006
70003       2480.4      2012-10-10  3009         5003
70012       250.45      2012-06-27  3008         5002
70011       75.29       2012-08-17  3003         5007
70013       3045.6      2012-04-25  3002         5001

customer_id  cust_name     city        grade       salesman_id
-----------  ------------  ----------  ----------  -----------
3002         Nick Rimando  New York    100         5001
3005         Graham Zusi   California  200         5002
3001         Brad Guzan    London      100         5005
3004         Fabian Johns  Paris       300         5006
3007         Brad Davis    New York    200         5001
3009         Geoff Camero  Berlin      100         5003
3008         Julian Green  London      300         5002
3003         Jozy Altidor  Moncow      200         5007

Sample Solution:

-- Selecting all columns from the 'orders' table and the 'cust_name' column from the 'customer' table
SELECT b.*, a.cust_name
-- Specifying the tables to retrieve data from ('orders' as 'b' and 'customer' as 'a')
FROM orders b, customer a
-- Filtering the results based on the condition that 'customer_id' is the same in both tables and 'ord_date' is '2012-08-17'
WHERE a.customer_id = b.customer_id
AND b.ord_date = '2012-08-17';

Output of the Query:

ord_no	purch_amt	ord_date	customer_id	salesman_id	cust_name
70004	110.50		2012-08-17	3009		5003		Geoff Cameron
70011	75.29		2012-08-17	3003		5007		Jozy Altidor

Explanation:

The said SQL query is selecting all columns from the 'orders' table (aliased as 'b') and the "cust_name" column from the 'customer' table (aliased as 'a') where the "customer_id" column in the 'customer' table matches the "customer_id" column in the 'orders' table and the "ord_date" column in the 'orders' table is equal to '2012-08-17'.
It is using a JOIN operation to combine the data from both tables based on the matching customer_id.

Visual Explanation:

Practice Online

Sample Database: inventory

Query Visualization:

Duration:

Rows:

Cost:

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