SQL Exercises: Find departments with more than two employees
SQL SUBQUERY: Exercise-38 with Solution
38. From the following tables write a SQL query to find which departments have more than two employees. Return dpt_name.
Sample table: emp_departmentDPT_CODE DPT_NAME DPT_ALLOTMENT -------- --------------- ------------- 57 IT 65000 63 Finance 15000 47 HR 240000 27 RD 55000 89 QC 75000Sample table: emp_details
EMP_IDNO EMP_FNAME EMP_LNAME EMP_DEPT --------- --------------- --------------- ---------- 127323 Michale Robbin 57 526689 Carlos Snares 63 843795 Enric Dosio 57 328717 Jhon Snares 63 444527 Joseph Dosni 47 659831 Zanifer Emily 47 847674 Kuleswar Sitaraman 57 748681 Henrey Gabriel 47 555935 Alex Manuel 57 539569 George Mardy 27 733843 Mario Saule 63 631548 Alan Snappy 27 839139 Maria Foster 57
Sample Solution:
-- Selecting the 'dpt_name' column from the 'emp_department' table
SELECT dpt_name FROM emp_department
-- Filtering the results based on the condition that 'dpt_code' is in the set of 'emp_dept' values returned by a subquery
WHERE dpt_code IN
(
-- Subquery: Selecting 'emp_dept' values from 'emp_details' and grouping by 'emp_dept' with a condition on the count of occurrences
SELECT emp_dept
FROM emp_details
GROUP BY emp_dept
HAVING COUNT(*) > 2
);
Output of the Query:
dpt_name IT HR Finance
Explanation:
The said SQL query that retrieves the names of departments from the 'emp_department' table where the department code is found in a subquery.
Using the subquery, all employees' department codes are selected from the 'emp_details' table, grouped by department, and then only those with more than two employees are selected.
The main query then uses the IN operator to check if the department codes from the subquery match any department codes in the 'emp_department' table and returns the corresponding department names.
Visual Explanation:
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Previous SQL Exercise: Departments with a sanction amount higher than average.
Next SQL Exercise: Employees working with the lowest sanction amount.
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