SQL Subquery Exercises: Counts the customers per grade with grades above New York's average
SQL SUBQUERY : Exercise-8 with Solution
8. Write a query to count the customers with grades above New York's average.
Sample table: Customer
SELECT grade, COUNT (*) FROM customer GROUP BY grade HAVING grade > (SELECT AVG(grade) FROM customer WHERE city = 'New York');
grade count 200 3 300 2
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