SQLite Exercise: Get the average salary for each job ID excluding programmer
Write a query to get the average salary for each job ID excluding programmer.
Sample table : employees
+-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+ | EMPLOYEE_ID | FIRST_NAME | LAST_NAME | EMAIL | PHONE_NUMBER | HIRE_DATE | JOB_ID | SALARY | COMMISSION_PCT | MANAGER_ID | DEPARTMENT_ID | +-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+ | 100 | Steven | King | SKING | 515.123.4567 | 1987-06-17 | AD_PRES | 24000.00 | 0.00 | 0 | 90 | | 101 | Neena | Kochhar | NKOCHHAR | 515.123.4568 | 1987-06-18 | AD_VP | 17000.00 | 0.00 | 100 | 90 | | 102 | Lex | De Haan | LDEHAAN | 515.123.4569 | 1987-06-19 | AD_VP | 17000.00 | 0.00 | 100 | 90 | | 103 | Alexander | Hunold | AHUNOLD | 590.423.4567 | 1987-06-20 | IT_PROG | 9000.00 | 0.00 | 102 | 60 | | 104 | Bruce | Ernst | BERNST | 590.423.4568 | 1987-06-21 | IT_PROG | 6000.00 | 0.00 | 103 | 60 | | 105 | David | Austin | DAUSTIN | 590.423.4569 | 1987-06-22 | IT_PROG | 4800.00 | 0.00 | 103 | 60 | | 106 | Valli | Pataballa | VPATABAL | 590.423.4560 | 1987-06-23 | IT_PROG | 4800.00 | 0.00 | 103 | 60 | | 107 | Diana | Lorentz | DLORENTZ | 590.423.5567 | 1987-06-24 | IT_PROG | 4200.00 | 0.00 | 103 | 60 | | 108 | Nancy | Greenberg | NGREENBE | 515.124.4569 | 1987-06-25 | FI_MGR | 12000.00 | 0.00 | 101 | 100 | | 109 | Daniel | Faviet | DFAVIET | 515.124.4169 | 1987-06-26 | FI_ACCOUNT | 9000.00 | 0.00 | 108 | 100 | ........... | 206 | William | Gietz | WGIETZ | 515.123.8181 | 1987-10-01 | AC_ACCOUNT | 8300.00 | 0.00 | 205 | 110 | +-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+
SQLite Code:
-- Selecting the "job_id" and the average salary for each job, excluding 'IT_PROG'
SELECT job_id, AVG(salary)
-- Specifying the table from which to retrieve the data, in this case, "employees"
FROM employees
-- Filtering the results to include only rows where the job_id is not 'IT_PROG'
WHERE job_id <> 'IT_PROG'
-- Grouping the results by the "job_id" column
GROUP BY job_id;
Output:
job_id AVG(salary) ---------- ----------- AC_ACCOUNT 8300.0 AC_MGR 12000.0 AD_ASST 4400.0 AD_PRES 24000.0 AD_VP 17000.0 FI_ACCOUNT 7920.0 FI_MGR 12000.0 HR_REP 6500.0 MK_MAN 13000.0 MK_REP 6000.0 PR_REP 10000.0 PU_CLERK 2780.0 PU_MAN 11000.0 SA_MAN 12200.0 SA_REP 8350.0 SH_CLERK 3215.0 ST_CLERK 2785.0 ST_MAN 7280.0
Explanation:
The above SQLite query retrieves the "job_id" and the average salary for each job from the "employees" table, excluding those with the job ID 'IT_PROG'. The results are grouped by the "job_id" column, and the average salary is calculated for each unique job.
Here's a brief explanation of each part of SQLite code:
- SELECT clause:
- It selects the "job_id" and the average salary for each job.
- FROM clause:
- Specifies the table from which to retrieve the data, in this case, the "employees" table.
- WHERE clause:
- Filters the results to include only rows where the "job_id" is not equal to 'IT_PROG'. This means that employees with the job ID 'IT_PROG' are excluded from the calculation.
- GROUP BY clause:
- Groups the results by the "job_id" column. This means that the average salary is calculated separately for each unique job.
Go to:
PREV : Write a query to get the department ID and the total salary payable in each department.
NEXT : Write a query to get the total salary, maximum, minimum, average salary of employees (job ID wise), for department ID 90 only.
Practice SQLite Online
Model Database
Structure of 'hr' database :
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