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Swift Basic Programming Exercise: Convert the last three characters in upper case

Swift Basic Programming: Exercise-19 with Solution

Write a Swift program to convert the last three characters in upper case. If the string has less than 3 chars, lowercase whatever is there.

Pictorial Presentation:

Swift Basic Programming Exercise: Convert the last three characters in upper case.

Sample Solution:

Swift Code:

func case_str(_ input: String) -> String {
    if input.characters.count < 3
    {
        return input.lowercased()
    } 
    else
    {
        var newInput = input.characters
        var str1: String = ""
        let lastThree = newInput.suffix(3)
        newInput.removeLast(3)
        let lastThreeUpper = String(lastThree).uppercased()
        str1.append(contentsOf: newInput)
        str1.append(String(lastThree).uppercased())
        return str1
    }
}
print(case_str("Hi")) 
print(case_str("Hello there")) 
print(case_str("Is")) 
print(case_str("Python"))

Sample Output:

hi
Hello thERE
is
PytHON

Swift Programming Code Editor:

Improve this sample solution and post your code through Disqus

Previous: Write a Swift program that accept two positive integer values and test whether the larger value is in the range 20..30 inclusive, or return 0 if neither is in that range.
Next: Write a Swift program to check if the first instance of "a" in a given string is immediately followed by another "a".

What is the difficulty level of this exercise?



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