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C Exercises: Concatenate two arrays

C Array: Exercise-107 with Solution

Write a program in C to concatenate two given arrays of integers.
If this is as simple as array1 + array2, so be it.

Sample Data:
({ 10, 20, 30, 40, 50, 60 }, { 70, 80, 90, 100, 110, 120 }) -> "10 20 30 40 50 60 70 80 90 100 110 120"

Sample Solution:

C Code:

#include <stdlib.h>
#include <stdio.h>
#include <string.h>

#define CONCAT_ARRAY(TYPE, A, An, B, Bn) \
  (TYPE *)test((const void *)(A), (An), (const void *)(B), (Bn), sizeof(TYPE));

void *test(const void *a, size_t an,
                   const void *b, size_t bn, size_t s)
{
  char *p = malloc(s * (an + bn));
  memcpy(p, a, an*s);
  memcpy(p + an*s, b, bn*s);
  return p;
}

const int x[] = { 10, 20, 30, 40, 50, 60 };
const int y[] = { 70, 80, 90, 100, 110, 120 };
   
int main(void)
{
  unsigned int i;

  int *z = CONCAT_ARRAY(int, x, 6, y, 6);
  printf("Original arrays:\n");
  printf("Array-1:\n");
  for(int i = 0; i < 6; i++)
    printf("%d ", x[i]);
  printf("\nArray-2:\n");
  for(i = 0; i < 6; i++)
    printf("%d ", y[i]); 
  printf("\nConcatenate above arrays:\n");
  for(i = 0; i < 12; i++)
    printf("%d ", z[i]);
  free(z);
  return 0;
}

Sample Output:

Original arrays:
Array-1:
10 20 30 40 50 60 
Array-2:
70 80 90 100 110 120 
Concatenate above arrays:
10 20 30 40 50 60 70 80 90 100 110 120 

Flowchart:

Flowchart: Double its value and replace the next number with 0 if current and next value are same and shift all 0's to the end.

C Programming Code Editor:

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Previous C Programming Exercise: Array, shift all 0 to the end, double the value of next.
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C Programming: Tips of the Day

What's this =! operator?

That's two operators, = and !, not one. It might be an obfuscated way of writing

a = !b;
if (a) {					
    // whatever
}

setting a to the logical inverse of b, and testing whether the result is true (or, equivalently, whether b was false).

Or it might be a mistyping of a != b.

Ref : https://bit.ly/3iFvMln





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