C Exercises: Find the number occurring odd number of times in an array
C Array: Exercise-34 with Solution
Write a program in C to find the number occurring odd number of times in an array.
All numbers occur even number of times except one number which occurs odd number of times.
Pictorial Presentation:

Sample Solution:
C Code:
#include <stdio.h>
int findOddCountElem (int *arr1, int n )
{
int i, ResultXor = 0;
for(i = 0; i < n; i++)
{
ResultXor = ResultXor ^ arr1[i];
}
return ResultXor;
}
int main()
{
int i;
int arr1[] = {8, 3, 8, 5, 4, 3, 4, 3, 5};
int ctr = sizeof(arr1)/sizeof(arr1[0]);
printf("The given array is : ");
for(i = 0; i < ctr; i++)
{
printf("%d ", arr1[i]);
}
printf("\n");
printf("Number of odd number occur(s) : %d times.\n", findOddCountElem(arr1, ctr));
return 0;
}
Sample Output:
The given array is : 8 3 8 5 4 3 4 3 5 Number of odd number occur(s) : 3 times.
Flowchart :

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C Programming: Tips of the Day
C Programming - What is the argument for printf that formats a long?
Put an l (lowercased letter L) directly before the specifier.
unsigned long n; long m; printf("%lu %ld", n, m);
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