# C Exercises: Find the number occurring odd number of times in an array

## C Array: Exercise-34 with Solution

Write a program in C to find the number occurring odd number of times in an array.

All numbers occur even number of times except one number which occurs odd number of times.

**Visual Presentation:**

**Sample Solution:**

**C Code:**

```
#include <stdio.h>
// Function to find the element occurring odd number of times in the array using XOR operation
int findOddCountElem(int *arr1, int n) {
int i, ResultXor = 0;
// Performing XOR operation on all array elements
for (i = 0; i < n; i++) {
ResultXor = ResultXor ^ arr1[i];
}
return ResultXor; // Returns the element occurring odd number of times
}
// Main function
int main() {
int i;
int arr1[] = {8, 3, 8, 5, 4, 3, 4, 3, 5};
int ctr = sizeof(arr1) / sizeof(arr1[0]);
// Display the given array
printf("The given array is : ");
for (i = 0; i < ctr; i++) {
printf("%d ", arr1[i]);
}
printf("\n");
// Function call to find the element occurring odd number of times
printf("Number of odd number occur(s) : %d times.\n", findOddCountElem(arr1, ctr));
return 0;
}
```

Sample Output:

The given array is : 8 3 8 5 4 3 4 3 5 Number of odd number occur(s) : 3 times.

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