﻿ C : A sorted array contains an integer x more than n/2 times

# C Exercises: Find if a given integer x appears more than n/2 times in a sorted array of n integers

## C Array: Exercise-48 with Solution

Write a program in C to find out if a given integer x appears more than n/2 times in a sorted array of n integers.

Visual Presentation: Sample Solution:

C Code:

``````# include <stdio.h>
# include <stdbool.h>

// Function to check if 'x' appears more than n/2 times in arr1[]
bool ChkMajority(int arr1[], int arr_size, int x)
{
int i;
// Check if the last index is even or odd to decide the range
int last_index = arr_size % 2 ? (arr_size / 2 + 1) : (arr_size / 2);
for (i = 0; i < last_index; i++)
{
// Check if the element at current index and the corresponding element after mid point equals 'x'
if (arr1[i] == x && arr1[i + arr_size / 2] == x)
return true; // Return true if 'x' appears more than n/2 times
}
return false; // Return false if 'x' does not appear more than n/2 times
}

int main()
{
int arr1[] = {1, 3, 3, 5, 4, 3, 2, 3, 3};
int arr_size = sizeof(arr1) / sizeof(arr1);
int x = 3, i;

// Print the given array
printf("The given array is :  ");
for (i = 0; i < arr_size; i++)
{
printf("%d  ", arr1[i]);
}
printf("\n");
printf("The given value is :  %d\n", x);

// Check if 'x' appears more than n/2 times in the array
if (ChkMajority(arr1, arr_size, x))
printf("%d appears more than %d times in the given array[]", x, arr_size / 2);
else
printf("%d does not appear more than %d times in the given array[]", x, arr_size / 2);

return 0;
}
```
```

Sample Output:

```The given array is :  1  3  3  5  4  3  2  3  3
The given value is :  3
3 appears more than 4 times in the given array[]
```

Flowchart: C Programming Code Editor:

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.

﻿