C Exercises: Print a matrix in spiral form
Write a program in C to print a matrix in spiral form.
This task involves writing a C program to print a given matrix in spiral order. The program will take a 2D array as input, display the matrix in its original form, and then output the elements in a spiral traversal order starting from the top-left corner.
Visual Presentation:
Sample Solution:
C Code:
#include <stdio.h>
#define R 4 // Number of rows in the matrix
#define C 5 // Number of columns in the matrix
// Function to print the elements of the matrix in a spiral order
void spiralOfMatrix(int enrow, int encol, int arr1[R][C])
{
int i, rowind = 0, colind = 0;
// Loop through the matrix elements in a spiral pattern
while (rowind < enrow && colind < encol)
{
// Print elements of the first row
for (i = colind; i < encol; ++i)
{
printf("%d ", arr1[rowind][i]);
}
rowind++;
// Print elements of the last column
for (i = rowind; i < enrow; ++i)
{
printf("%d ", arr1[i][encol - 1]);
}
encol--;
// Print elements of the last row if it is within matrix boundaries
if (rowind < enrow)
{
for (i = encol - 1; i >= colind; --i)
{
printf("%d ", arr1[enrow - 1][i]);
}
enrow--;
}
// Print elements of the first column if it is within matrix boundaries
if (colind < encol)
{
for (i = enrow - 1; i >= rowind; --i)
{
printf("%d ", arr1[i][colind]);
}
colind++;
}
}
}
int main()
{
int i, j;
int arr1[R][C] = {
{1, 2, 3, 4, 5},
{6, 7, 8, 9, 10},
{11, 12, 13, 14, 15},
{16, 17, 18, 19, 20}
};
// Print the original matrix
printf("The given array in matrix form is:\n");
for (i = 0; i < R; i++)
{
for (j = 0; j < C; j++)
{
printf("%d ", arr1[i][j]);
}
printf("\n");
}
printf("\n");
// Print the matrix in spiral order
printf("The spiral form of the above matrix is:\n");
spiralOfMatrix(R, C, arr1);
return 0;
}
Sample Output:
The given array in matrix form is : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 The spiral form of above matrix is: 1 2 3 4 5 10 15 20 19 18 17 16 11 6 7 8 9 14 13 12
Flowchart:
C Programming Code Editor:
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