C Exercises: Find the median of two sorted arrays of same size

C Array: Exercise-64 with Solution

Write a program in C to find the median of two sorted arrays of the same size.

Sample Solution:

C Code:

#include <stdio.h>

int max(int a, int b) 
{
   return ((a > b) ? a : b);
}
int min(int a, int b) 
{
   return ((a < b) ? a : b);
}
int median(int arr[], int size) 
{
   if (size % 2 == 0)
         return (arr[size/2] + arr[size/2-1])/2;
   else
         return arr[size/2];
}
int median2SortedArrays(int arr1[], int arr2[], int size) 
{
   int med1;
   int med2;
   if(size <= 0) return -1;
   if(size == 1) return (arr1[0] + arr2[0])/2;
   if (size == 2) return (max(arr1[0], arr2[0]) + min(arr1[1], arr2[1])) / 2;

   med1 = median(arr1, size); 
   med2 = median(arr2, size); 

   if(med1 == med2) return med1;

   if (med1 < med2) 
   {
      return median2SortedArrays(arr1 + size/2, arr2, size - size/2);
   }
   else 
   {
      return median2SortedArrays(arr2 + size/2, arr1, size - size/2);
   }
}

int main() 
{
   int i,m,n;
   int arr1[] = {1, 5, 13, 24, 35};
   int arr2[] = {3, 8, 15, 17, 32};
   m = sizeof(arr1) / sizeof(arr1[0]);
   n = sizeof(arr2) / sizeof(arr2[0]);	   
	//------------- print original array ------------------	
	printf("The given array - 1 is :  ");
	for(i = 0; i < m; i++)
	{
	printf("%d  ", arr1[i]);
    } 
	printf("\n");
//------------------------------------------------------  
	printf("The given array - 2 is :  ");
	for(i = 0; i < n; i++)
	{
	printf("%d  ", arr2[i]);
    } 
	printf("\n");
//------------------------------------------------------  
   printf("\nThe Median of the 2 sorted arrays is: %d",median2SortedArrays(arr1, arr2, n));
   printf("\n");
   return 0;
}

Sample Output:

The given array - 1 is :  1  5  13  24  35  
The given array - 2 is :  3  8  15  17  32  

The Median of the 2 sorted arrays is: 14 

Flowchart:

C Programming Code Editor:

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