C Exercises: Find the median of two sorted arrays of same size
C Array: Exercise-64 with Solution
Write a program in C to find the median of two sorted arrays of the same size.
Sample Solution:
C Code:
#include <stdio.h>
int max(int a, int b)
{
return ((a > b) ? a : b);
}
int min(int a, int b)
{
return ((a < b) ? a : b);
}
int median(int arr[], int size)
{
if (size % 2 == 0)
return (arr[size/2] + arr[size/2-1])/2;
else
return arr[size/2];
}
int median2SortedArrays(int arr1[], int arr2[], int size)
{
int med1;
int med2;
if(size <= 0) return -1;
if(size == 1) return (arr1[0] + arr2[0])/2;
if (size == 2) return (max(arr1[0], arr2[0]) + min(arr1[1], arr2[1])) / 2;
med1 = median(arr1, size);
med2 = median(arr2, size);
if(med1 == med2) return med1;
if (med1 < med2)
{
return median2SortedArrays(arr1 + size/2, arr2, size - size/2);
}
else
{
return median2SortedArrays(arr2 + size/2, arr1, size - size/2);
}
}
int main()
{
int i,m,n;
int arr1[] = {1, 5, 13, 24, 35};
int arr2[] = {3, 8, 15, 17, 32};
m = sizeof(arr1) / sizeof(arr1[0]);
n = sizeof(arr2) / sizeof(arr2[0]);
//------------- print original array ------------------
printf("The given array - 1 is : ");
for(i = 0; i < m; i++)
{
printf("%d ", arr1[i]);
}
printf("\n");
//------------------------------------------------------
printf("The given array - 2 is : ");
for(i = 0; i < n; i++)
{
printf("%d ", arr2[i]);
}
printf("\n");
//------------------------------------------------------
printf("\nThe Median of the 2 sorted arrays is: %d",median2SortedArrays(arr1, arr2, n));
printf("\n");
return 0;
}
Sample Output:
The given array - 1 is : 1 5 13 24 35 The given array - 2 is : 3 8 15 17 32 The Median of the 2 sorted arrays is: 14
Flowchart:

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Next: Write a program in C to find the product of an array such that product is equal to the product of all the elements of arr[] except arr[i].
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C Programming: Tips of the Day
C Programming - What is the argument for printf that formats a long?
Put an l (lowercased letter L) directly before the specifier.
unsigned long n; long m; printf("%lu %ld", n, m);
Ref : https://bit.ly/3dIwfkP
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